Answer:
Option 4 is correct.
Step-by-step explanation:
Consider a function g, it has a domain of -1 ≤ x ≤ 4 and a range of 0 ≤ g(x) ≤ 18. It is given that g(-1) = 2 and g(2) = 8.
The statement g(5) = 12 is not true because the value of x is 5 which is not in its domain.
The statement g(1) = -2 is not true because the value of function g(x) is -2 which is not in its range.
The statement g(2) = 4 is not true because g is a function and each function has unique output for each input value.
If g(2)=8 and g(2)=4, then the value of g(x) is 8 and 4 at x=2. It means g(x) is not a function, which is contradiction of given statement.
The statement g(3) = 18 is true because the value of x is 3 which is in the domain and the value of function g(x) is 18 which is in its range.
Therefore, the correct option is 4.
She had 45$ before she spent it. 30+15
Answer:
520 miles
Step-by-step explanation:
Answer:
Therefore, the conclusion is valid.
The required diagram is shown below:
Step-by-step explanation:
Consider the provided statement.
Premises: All good students are good readers. Some math students are good students.
Conclusion: Some math students are good readers.
It is given that All good students are good readers, that means all good students are the subset of good readers.
Now, it is given that some math students are good students, that means there exist some math student who are good students as well as good reader.
Therefore, the conclusion is valid.
The required diagram is shown below:
Answer:
<em><u>First</u></em><em><u> </u></em><em><u>Column</u></em><em><u> </u></em><em><u>top</u></em><em><u>:</u></em>
5. 3. 10
<em><u>Second</u></em><em><u> </u></em><em><u>Column</u></em><em><u> </u></em><em><u>middle</u></em><em><u>:</u></em>
9. 7. 2
<em><u>Third</u></em><em><u> </u></em><em><u>Column</u></em><em><u> </u></em><em><u>bottom</u></em><em><u>:</u></em>
4. 8. 6
<em><u>Hence</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>grid</u></em><em><u> </u></em><em><u>would</u></em><em><u> </u></em><em><u>be</u></em><em><u>,</u></em>
5. 3. 10
9. 7. 2
4. 8. 6