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creativ13 [48]
3 years ago
12

Which is equivalent to

ula1" title="\sqrt[4]{9} ^{\frac{1}{2}x }" alt="\sqrt[4]{9} ^{\frac{1}{2}x }" align="absmiddle" class="latex-formula">
A: 9^{2x}
B:9^{\frac{1}{8}x }
C:\sqrt{9}^{x}
D:\sqrt[6]{9}  ^{x}



ANSWER IS B: :9^{\frac{1}{8}x }
Mathematics
1 answer:
Digiron [165]3 years ago
5 0

For this case we have that by definition of properties of powers and roots, it is fulfilled that:

\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}

So:

\sqrt [4] {9 ^ {\frac {1} {2} x}} = 9 ^ {\frac {\frac {1} {2}} {4} x} = 9 ^ {\frac {1} {8} x}

So, we have to:

\sqrt [4] {9 ^ {\frac {1} {2} x}} = 9 ^ {\frac {1} {8} x}

Answer:

9 ^ {\frac {1} {8} x}

Option B

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what is the radians per seconds "w" in revolutions per minute?  just another conversion like in 13)

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Step-by-step explanation:

First, replace f(x) with y

Replace every x with a y and replace every y with an x .

Solve the equation from Step 2 for y  

Replace y with f−1(x) f − 1 ( x )

Verify your work by checking that (f∘f−1)(x)=x ( f ∘ f − 1 ) ( x ) = x and (f−1∘f)(x)=x ( f − 1 ∘ f ) ( x ) = x are both true.

Hope this helps!  Stay Safe!

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Answer:

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Read 2 more answers
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