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Vsevolod [243]
3 years ago
7

What is the slope of the line that passes through (5,-2) and (-3,4)

Mathematics
1 answer:
kolezko [41]3 years ago
3 0

Answer:

Slope =  \frac{-3}{4}

Step-by-step explanation:

(5 , -2)   ; (-3, 4)

Slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{4-[-2]}{-3-5}\\\\=\frac{4+2}{-3-5}\\\\=\frac{6}{-8}\\\\=\frac{-3}{4}\\\\

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Compare and contrast the absolute value of a real number to that of a complex number.
sveticcg [70]
The absolute value of a real number is a positive value of the number. Which means that the absolute value is the distance from zero of the number line. However, that of the complex numbers is the distance from the origin to the point in a complex plane. 
4 0
3 years ago
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40% of the students in a class are girls and the number of boys is 24 find the total number of students and the number of girls​
navik [9.2K]

Answer:

Girls = 16

Total students = 40

Step-by-step explanation:

40% of the students are girls, this means 60% of the students are boys.

To find the number of girls, setup a proportion using the percentages and actual number of students in the class. I am going to make the numerator the numbers that go with the girls and the denominator will be the numbers that go with the boys.

Also let's convert the percentages to decimals by moving the decimal two places left.

40% = 0.4 and 60% = 0.6

\frac{.4}{.6} =\frac{g}{24} \\.6g=9.6\\\frac{.6g}{.6} =\frac{9.6}{.6} \\g=16

Now let's find the total number of students by adding the number of girls to the number of boys.

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7 0
1 year ago
2 1/2 divided by 1 5/8? I forgot how to divide fractions and simplify them....please help
nlexa [21]
2\frac{1}{2}:1\frac{5}{8}=\frac{2\times2+1}{2}:\frac{1\times8+5}{8}=\frac{5}{2}:\frac{13}{8}=\frac{5}{\not2_1}\times\frac{\not8^4}{13}=\frac{5}{1}\times\frac{4}{13}=\frac{5\times4}{1\times13}=\frac{20}{13}=1\frac{7}{13}
3 0
3 years ago
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A circle graph has five
Norma-Jean [14]

Answer:

the missing section is 49%

Step-by-step explanation:

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4 0
2 years ago
Shania and Pedro are discussing whether it is always possible to solve a right triangle, given enough information, without using
Makovka662 [10]

Answer: Shania is correct.

Step-by-step explanation:

For a right angled triangle, given two sides and an angle, we can use the sine rule or the various trigonometry identities to solve the triangle;

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and

sin (angle) = opposite side/hypotenuse

cos (angle) = adjacent side/hypotenuse

tan (angle) = opposite/ adjacent

assuming a is the opposite side of angle A and b is also opposite of angle B

Otherwise, the only way to solve a triangle given two sides only is by the use of the Pythagoras theorem.

Hence, Shania is correct.

7 0
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