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3 years ago

7

What is the slope of the line that passes through (5,-2) and (-3,4)

1 answer:

kolezko [41]3 years ago

3 0

Answer:

Slope = $\frac{-3}{4}$

Step-by-step explanation:

(5 , -2) ; (-3, 4)

$Slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{4-[-2]}{-3-5}\\\\=\frac{4+2}{-3-5}\\\\=\frac{6}{-8}\\\\=\frac{-3}{4}\\\\$

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Answer:

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Step-by-step explanation:

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Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

strojnjashka [21]

Answer:

The missing side is $B = 6.0\ cm$

The missing angles are $\alpha = 56.2$ and $\theta = 93.8$

Step-by-step explanation:

Given

$A = 10\ cm$

$C = 12\ cm$

$\beta = 30$

The implication of this question is to solve for the missing side and the two missing angles

Represent

Angle A with $\alpha$

Angle B with $\beta$

Angle C with $\theta$

Calculating B

This will be calculated using cosine formula as thus;

$B^2 = A^2 + C^2 - 2ACCos\beta$

Substitute values for A, C and $\beta$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 * Cos30$

$B^2 = 100 + 144 - 240 * 0.8660$

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Take Square root of both sides

$B = \sqrt{36.2}$

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This will be calculated using cosine formula as thus;

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute values for A, B and C

$A^2 = B^2 + C^2 - 2BCCos\alpha$

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Collect Like Terms

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Divide both sides by -144

$\frac{-80}{-144} = Cos\alpha$

$0.5556 = Cos\alpha$

$\alpha = cos^{-1}(0.5556)$

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This will be calculated using cosine formula as thus;

$C^2 = B^2 + A^2 - 2BACos\theta$

Substitute values for A, B and C

$12^2 = 6^2 + 10^2 - 2 * 6 * 10Cos\theta$

$144 = 36 + 100 - 120Cos\theta$

Collect Like Terms

$144 - 36 - 100 = -120Cos\theta$

$8 = -120Cos\theta$

Divide both sides by -120

$\frac{8}{-120} = Cos\theta$

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3 years ago

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kotegsom [21]

Answer and Step-by-step explanation:

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disa [49]

Answer:

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