Answer:
Use the distance formula on both points AC and AB.
<em>Distance formula is this</em><em>:</em>
<em>\begin{gathered}d=\sqrt{(x2-x1)^2+(y2-y1)^2} \\\\d=\sqrt{(1--5)^2+(8--7)^2} \\\\d=\sqrt{(6)^2+(15)^2} \\\\d=\sqrt{36+225} \\\\d=\sqrt{261} \\\\\end{gathered}d=(x2−x1)2+(y2−y1)2d=(1−−5)2+(8−−7)2d=(6)2+(15)2d=36+225d=261</em>
Distance for AC is 16.16
Now do the same with the numbers for AB and get the distance of 5.39
2. To get the area, use the formula 1/2 x base x height
AB is the base and AC is the height.
1/2 x 16.16 x 5.39 = 43.55
the answer is 43.5
Answer:
Your answer would be 9
Step-by-step explanation:
hope this helps
pls mak brainliest
Answer:
The x-intercept is at the point (5,0).
Step-by-step explanation:
-2x + 5y = -10
At the x intercept y = 0 so we substitute y = 0 into the given equation:
-2x + 5(0) = -10
-2x = -10
x = 5.
