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Nookie1986 [14]
3 years ago
6

Solution for x=5-y and x+y=15

Mathematics
1 answer:
zimovet [89]3 years ago
7 0
It might be no solution:

steps-

x=5-y
x+y=15

substitute the x(which is the top problem) into the second one.

(5-y)+y=15

cancel it out

(5-y)+y=15
-5. -5

a negative plus a positive is gonna equal 0

-y+y=15-5

0=10

that is no solution..
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Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

Step-by-step explanation:

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Number of student who has passed Exam FM/2 = 1

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According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.

So, Probability will be

\frac{^6C_3\times ^2C_1}{^8C_4}\\\\=\frac{20\times 2}{70}\\\\=\frac{4}{7}\\\\=0.57

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

4 0
3 years ago
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Answer:

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5 0
2 years ago
If a and b are independent events with p(a) = 0.05 and p(b) = 0.65, then the conditional probability p(a |
alukav5142 [94]
Two events are said to be independent when the occurence of one event does not in any way affects the occurence of the other event.

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3 years ago
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I hope this helps.
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