How many solutions does the following equation have?

Vugar has a maximum of 30 batteries for toys. Each toy helicopter uses the same number of batteries, and each toy car uses the s

Leno4ka [110]

Answer: 3H+4C<_ 30

The coefficients of the variables H and C represent the number of batteries each toy helicopter and each toy car uses.

Step-by-step explanation:

Each toy helicopter uses 3 batteries, and each toy car uses 4 batteries.

Now let's check whether Vugar has enough batteries for 5 toy helicopters and 4 toy cars. To do this, we substitute H=5 and C= 4 in the given inequality:

Does Vugar have enough batteries to play with 5 toy helicopters and 4 toy cars?

No, because if you plug in the value for H and C:

3H + 4C<_ 30

3(5) + 4(4) <_30

15 + 16 <_ 30

31 <_ 30; false

Since the inequality is false, Vugar does not have enough batteries to play with 555 toy helicopters and 444 toy cars.

Each toy helicopter uses 333 batteries, and each toy car uses 444 batteries.

No, Vugar does not have enough batteries to play with 555 toy helicopters and 444 toy cars.

6 0

4 years ago

Read 2 more answers

Miguel is a golfer, and he plays on the same course each week. The following table shows the probability distribution for his sc

aivan3 [116]

1) 4.55

2) Short hit

Step-by-step explanation:

1)

The table containing the score and the relative probability of each score is:

Score 3 4 5 6 7

Probability 0.15 0.40 0.25 0.15 0.05

Here we call

X = Miguel's score on the Water Hole

The expected value of a certain variable X is given by:

$E(X)=\sum x_i p_i$

where

$x_i$ are all the possible values that the variable X can take

$p_i$ is the probability that $X=x_i$

Therefore in this problem, the expected value of MIguel's score is given by:

$E(X)=3\cdot 0.15 + 4\cdot 0.40 + 5\cdot 0.25 + 6\cdot 0.15 + 7\cdot 0.05=4.55$

2)

In this problem, we call:

X = Miguel's score on the Water Hole

Here we have that:

- If the long hit is successfull, the expected value of X is

$E(X)=4.2$

- Instead, if the long hit fails, the expected value of X is

$E(X)=5.4$

Here we also know that the probability of a successfull long hit is

$p(L)=0.4$

Which means that the probabilty of an unsuccessfull long hit is

$p(L^c)=1-p(L)=1-0.4=0.6$

Therefore, the expected value of X if Miguel chooses the long hit approach is:

$E(X)=p(L)\cdot 4.2 + p(L^C)\cdot 5.4 = 0.4\cdot 4.2 + 0.6\cdot 5.4 =4.92$

In part 1) of the problem, we saw that the expected value for the short hit was instead

$E(X)=4.55$

Since the expected value for X is lower (=better) for the short hit approach, we can say that the short hit approach is better.

8 0

3 years ago

Quando existe, dizemos que a solução de um sistema de equações lineares é o conjunto ordenado de números que satisfaz todas as e

QveST [7]

X representa o numero das suas respostas certas.
y represnta o numero das suas respostas erradas.
O total de perguntas é 25, portanto
x + y = 25

Agora tratamos do dinheiro.
Começa com R$ 500,00
Pelas x respostas certas, recebe 200x.
Pelas y respostas errads perde 150y.
O total de dineheiro inicial mais os ganhos menos as perdas são iguais a
R$ 600,00, portanto
500 + 200x - 150y = 600
200x - 150y = 100
20x - 15y = 10

Temos um sistema de duas equações com duas variaveis.

x + y = 25
20x - 15y = 10

15x + 15y = 375
+ 20x - 15y = 10
---------------------------
 35x = 385
 x = 11

x + y = 25

11 + y = 25

y = 14

Resposta: Errou 14 perguntas.

5 0

4 years ago

Tell whether the ratios form a proportion.

qaws [65]

5:16 is no
24:15 is no
3:12 is yes

3 0

3 years ago

PLZ help SOMEONE!! IM CONFUSED :/ In two or more complete sentences, explain how to find the interval(s) in which the function f

Sedbober [7]

Decreaseing means where it is going down
those blank points mean not including
brackets mean inlclude, it's like the ≤ or ≥ sign
parenthasees means not include, it's like the < or > sign

it is going down from -8 to -5, not including -5 so [-8,-5)
also going down from 4 to 8, not including 8, so [4,8)
the union is including both

[-8,-5) U [4,8) is answer for where the function is decreasing

6 0

4 years ago