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melamori03 [73]
3 years ago
15

Can anybody please help me show my work for these problems....I have the correct answer just no work to prove it...

Mathematics
2 answers:
Anon25 [30]3 years ago
7 0
<span>1)
f(x) = x^2 + 2x
So lets replace all the x parts with (a-3) f(a-3) = (a-3)^2 + 2(a-3)
and the rest is just expanding it out from there.
</span>A: a^2-4a+3<span>

</span>2. If f(x0=x/x-3 and g(x)=2x-1, find (f-g)(x)
A: -2x^2+8x-3/x-3

3. If f(x)=x^2+1 and g(x)=1/x, find [f*g](x)
A:1/x^2 +1

4. Which equation best represents a line perpendicular to the graph of x+3y=9?
A:y=3x-1

5. Which of the following describes the graphs of 2x+5y=9 and 10x=4y+18?
A: perpendicular

6. Write the standard form of an equation of the line parallel to the graph of x-2y-6=0 and passing through A(-3,2)
 A: x-2y+7=0
Nikitich [7]3 years ago
5 0
I hope this helps you

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\large\boxed{B.\ f(x)=4^x}

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7 0
3 years ago
The length of the base of a triangle is twice its height. if the area of the triangle is 196 square​ kilometers, find the height
NISA [10]
Area = 1/2 x base x height

Let the height be x.
Height = x
Base = 2x

Area of triangle = 1/2 x base x  heght

Plug base and height into the variables:
(1/2)(2x)(x) = 196

Combine like terms:
x² = 196

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Answer: Height = 28km
4 0
3 years ago
Read 2 more answers
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