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GenaCL600 [577]
3 years ago
15

According to the FDA, products labeled gluten-free must contain less than _______ of gluten.

Health
2 answers:
OLga [1]3 years ago
8 0

According to the FDA, products labeled gluten-free must contain less than 20 milligrams of gluten. Have a nice day!

Serggg [28]3 years ago
4 0
According to the FDA, food products labeled "gluten-free" or "no gluten" must contain at least 20 parts per million in order to be in an acceptable range. Especially since people with celiac disease, when the small intestine is sensitive to gluten, can only tolerate a tiny amount.
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Which is a characteristic of a gang?
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Seeks control of a defined territory
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An alcohol awareness program sponsored by a local police department is an example of a __________.
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<span>An alcohol awareness program sponsored by a local police department is an example of a community program. The correct option is A. A community program is a social service provided for a specific community typically by providers who reside in that same community.</span>
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What can Bruno do to get adequate sleep each night? Check all that apply.
erastovalidia [21]

Explanation:

Bruno should

Try to spend some time outdoors every day.

Plan his physical activity for earlier in the day, not right before he goes to bed.

Stay away from caffeine (including coffee, tea, and soda) late in the day.

If he has trouble sleeping at night, limit daytime naps to 20 minutes or less.

3 0
3 years ago
Two parents who are heterozygous for type A blood and have sickle cell trait have children.
GuDViN [60]

This question is incomplete, but here is the complete question below.

In humans , blood type is a result of multiple alleles: I^{A}, I^{B}, i^{o}.

A few simple rules of blood type genetics are that:

I^{A} is dominant over i^{o}

I^{B} is dominant over i^{o}, and

I^{A}I^{B} are codominant

Two plants who are heterozygous for type A blood and have sickle cell trait have children. Answer the following questions:

a. What is the genotype of the parents?

b. What are the genetic make ups of all the possible gametes they can produce.

c. Complete the dihybrid Punnet square to determine the frequency of the different phenotypes in the offspring.

(NOTE: Consider blood type and normal versus mutant hemoglobin in the various phenotypes.)

Answer:

a) I^{A}i^{o}AS

b) I^{A}A,I^{A}S,i^{o}A,i^{o}S

c) The dihybrid table is shown in the explanation below and the frequency of the different phenotypes of the offspring are in the ratio of 3:6:3:1:2:1

Explanation:

a)

From the question the genotype of the parents can be determined:

Given that Two parents are heterozygous for  type  A and have sickle cell trait.

∴ heterozygous for  type  A will be  = I^{A}i^{o} &

heterozygous for having sickle cell traits = AS

Therefore, the traits can be determined the genotype of the parents can be determined as: I^{A}i^{o}AS

b)

the genetic make ups of all the possible gametes they can produce can be determined if the parent are self crossed.

If I^{A}i^{o}AS self crossed, we have:

                I^{A}                 i^{o}

A              I^{A}A               i^{o}A

S              I^{A}S                i^{o}S

∴ The genetic makeups of all the possible gametes they can produce are:

I^{A}A, I^{A}S, i^{o}A, i^{o}S

c)

Below shows the dihybrid Punnet square and  the frequency of the different phenotypes in the offspring

               I^{A}A               I^{A}S                    i^{o}A                 i^{o}S

I^{A}A     I^{A}I^{A}AA     I^{A}I^{A}AS        I^{A}i^{o}AA        I^{A}i^{o}AS

I^{A}S     I^{A}I^{A}AS      I^{A}I^{A}SS         I^{A}i^{o}AS        I^{A}i^{o}SS

i^{o}A     I^{A}i^{o}AA      I^{A}i^{o}AS         i^{o}i^{o}AA        i^{o}i^{o}AS

i^{o}S     I^{A}i^{o}AS       I^{A}i^{o}SS         i^{o}i^{o}AS         i^{o}i^{o}SS

\frac{3}{16}= 18.75% : Blood type A, normal hemoglobin (normal RBCs) = I^{A}I^{A}AA, I^{A}i^{o}AA, I^{A}i^{o}AA

\frac{6}{16}= 37.5% : Blood type A, normal and mutant hemoglobin (sickle cell trait) = I^{A}I^{A}AS, I^{A}i^{o}AS, I^{A}I^{A}AS, I^{A}i^{o}AS, I^{A}i^{o}AS, I^{A}i^{o}AS

\frac{3}{16}= 18.75% : Blood type A, mutant hemoglobin (sickle cell anemia) = I^{A}I^{A}SS, I^{A}i^{o}SS, I^{A}i^{o}SS

\frac{1}{16}= 6.25% : Blood type O, normal hemoglobin (normal RBCs) = i^{o}i^{o}AA

\frac{2}{16}= 12.5% : Blood type O, Blood type A, normal and mutant hemoglobin (sickle cell trait) = i^{o}i^{o}AA, i^{o}i^{o}AS

\frac{1}{16}= 6.25% : Blood type O, mutant hemoglobin (sickle cell anemia) = i^{o}i^{o}SS

I hope that helps alot!

3 0
3 years ago
The ability of a muscle to contract and relax is dependent on the flow of what substance out of and into its storage site in the
tiny-mole [99]

Answer:

Calcium.

Explanation:

Muscle cells are the important for the body as they are involved in the bodily movement. Three different type of muscle are smooth muscle, cardiac muscle and skeletal muscle.

The sarcoplasmic reticulum contains the stored calcium in the muscle cell. The calcium is important ion that plays an important role in the muscle contraction. The actin and myosin protein functioning also depends on the the calcium ion.

Thus, the correct answer is option (B).

4 0
3 years ago
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