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3 years ago

64 w^2 + 96w+36=0. What is the number of real solutions?

Mathematics

2 answers:

patriot [66]3 years ago

5 0

Answer:

1 solution multiplicity 2.

Step-by-step explanation:

64 w^2 + 96w+36=0 Divide through by 4:

16w^2 + 24w + 9 = 0

The value of the discriminant = b^2 - 4ac

= 24^2 - 4*16*9

= 0.

This means there is only 1 real solution of multiplicity 2.

The graph will just touch the x - axis at one point

7nadin3 [17]3 years ago

4 0

Answer:

w = -3/4 or -0.75

there is only one solution

Step-by-step explanation:

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