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Gala2k [10]
3 years ago
12

64 w^2 + 96w+36=0. What is the number of real solutions?

Mathematics
2 answers:
patriot [66]3 years ago
5 0

Answer:

1 solution multiplicity 2.

Step-by-step explanation:

64 w^2 + 96w+36=0  Divide through by 4:

16w^2 + 24w + 9 = 0

The value of the discriminant =  b^2 - 4ac

= 24^2 - 4*16*9

=  0.

This  means there is only 1 real solution of multiplicity 2.

The graph will just touch the x - axis at one point

7nadin3 [17]3 years ago
4 0

Answer:

w = -3/4 or -0.75

there is only one solution

Step-by-step explanation:

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3 years ago
Solve this quadratic formula -3x^2 +16 +12
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Solve for x over the real numbers:

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8 0
4 years ago
Read 2 more answers
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lidiya [134]
You'd have to draw a table of x and y values first to be able to graph.
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Follow these steps 2 more times to get at least three ordered pairs.

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6 0
3 years ago
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Korolek [52]

To solve the problem, simply plug in the value for x in both functions, as shown below:

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Step-by-step explanation:

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