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Gala2k [10]
3 years ago
12

64 w^2 + 96w+36=0. What is the number of real solutions?

Mathematics
2 answers:
patriot [66]3 years ago
5 0

Answer:

1 solution multiplicity 2.

Step-by-step explanation:

64 w^2 + 96w+36=0  Divide through by 4:

16w^2 + 24w + 9 = 0

The value of the discriminant =  b^2 - 4ac

= 24^2 - 4*16*9

=  0.

This  means there is only 1 real solution of multiplicity 2.

The graph will just touch the x - axis at one point

7nadin3 [17]3 years ago
4 0

Answer:

w = -3/4 or -0.75

there is only one solution

Step-by-step explanation:

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3 years ago
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Roman55 [17]

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Now, this set will be the set of solutions of:

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3 years ago
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