1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lisabon 2012 [21]
3 years ago
15

(10 pts) (a) (2 pts) What is the difference between an ordinary differential equation and an initial value problem? (b) (2 pts)

What is the difference between a particular solution and a general solution? (c) (3 pts) Given an example of a second-order linear ODE and a second-order nonlinear ODE that is not in the text, Chapter 1. (d) (3 pts) Give an example of a nonlinear 4th-order ordinary differential equation.
Mathematics
1 answer:
laiz [17]3 years ago
4 0

Answer:

Step-by-step explanation:

(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.

(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.

(C) Example of a second order linear ODE:

M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)

The equation will be homogeneous if K(t)=0 and heterogeneous if K(t)\neq 0

Example of a second order nonlinear ODE:

Y=-3K(Y){2}

(D) Example of a nonlinear fourth order ODE:

K^4(x) - \beta f [x, k(x)] = 0

You might be interested in
PLEASE HELLP ASAP!!! Will Mark Braniliest!!!
Tasya [4]

Answer:

1. 15

2. 17

ur welcome :)000))

4 0
3 years ago
Solve The Following Question:<br><br> 5/13t = -9
BabaBlast [244]
5/13t= -9
Then t =( -9*13) / 5
T=-23.4
3 0
3 years ago
Read 2 more answers
-5+(-8)-(6+9)-(6•4)
Fittoniya [83]

Answer:

-28

Step-by-step explanatio

7 0
2 years ago
Read 2 more answers
Find the length of HJ
Free_Kalibri [48]

Answer:

<h2>HJ = 17</h2>

Step-by-step explanation:

The equation:

2 + HI + 12 = 7 + 12

HI + 14 = 19             <em>subtract 14 from both sides</em>

HI = 5

HJ = HI + 12

Substitute the value of HI:

HJ = 5 + 12 = 17

4 0
3 years ago
Nine years ago, Tarah opened a savings account with her bank. She started with a balance of $450 and has not made any withdrawal
lesya [120]

Answer:

Step-by-step explanation:

The interest accrued is $258.48.

Step-by-step explanation:

Given that:

Initial balance in the savings account = $359

Interest rate = 8%

Time for which no withdrawals or deposits were done = 9 years

To find:

Simple Interest accrued = ?

Solution:

First of all, let us have a look at the formula for simple interest.

Where P is the Principal Amount.

R is the annual rate of interest

T is the time in years.

Here, we are given:

P = $359

R = 8%

T = 9 years

Let us put all the values in the formula:

So, the interest accrued is $258.48.

4 0
3 years ago
Other questions:
  • Please help me answer this !!!
    10·1 answer
  • A counter top is 18 feet long and 3 feet wide. What is the area of the counter top in square meters? Use the conversion 1 foot =
    11·1 answer
  • 2. Express the following in the form of a ratio and
    13·1 answer
  • Wich measure is less than 435 inches
    9·1 answer
  • Sara has $1.30 less than double what Billy does. Sara has $53.72. How much money does Billy have?​
    9·1 answer
  • Write a story problem for a number between 11 and 19. Then solve by using words from the Word List.Show your work ( word list---
    15·1 answer
  • 3.2.4 practice modeling slope-intercept Equation of a line
    12·1 answer
  • 12th term in sequence 23,43 ,63,83​
    14·2 answers
  • 8 yd<br> 6 yd<br> 15 yd<br> 10 yd<br> Answer:<br><br><br><br><br> please help!:)
    9·1 answer
  • Answer question 11 for me.
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!