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lisabon 2012 [21]
3 years ago
15

(10 pts) (a) (2 pts) What is the difference between an ordinary differential equation and an initial value problem? (b) (2 pts)

What is the difference between a particular solution and a general solution? (c) (3 pts) Given an example of a second-order linear ODE and a second-order nonlinear ODE that is not in the text, Chapter 1. (d) (3 pts) Give an example of a nonlinear 4th-order ordinary differential equation.
Mathematics
1 answer:
laiz [17]3 years ago
4 0

Answer:

Step-by-step explanation:

(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.

(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.

(C) Example of a second order linear ODE:

M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)

The equation will be homogeneous if K(t)=0 and heterogeneous if K(t)\neq 0

Example of a second order nonlinear ODE:

Y=-3K(Y){2}

(D) Example of a nonlinear fourth order ODE:

K^4(x) - \beta f [x, k(x)] = 0

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Step-by-step explanation:

A principal of $3600 is invested at 7.5% interest, compounded annually. How much will the investment be worth after 6 years?

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A(t)=P(1+\frac{r}{n})^{nt}

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Keywords: Compound Interest formula

Learn more about Compound Interest formula at:

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