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Marysya12 [62]
3 years ago
13

The following measurements are ranked from largest to smallest: 11.6 mg, 1021 µg, 0.000006 kg, 0.31 mg.

Physics
1 answer:
Fynjy0 [20]3 years ago
7 0

Answer 4:  False

Explanation:  

The following measurement given above (11.6 mg, 1021 µg, and 0.000006 kg, 0.31 mg) is a false statement. Henceforth the right configuration of rank from biggest to littlest are 11.6 mg, 0.000006 kg, 1021 µg, and 0.31 mg. Since 11.6 mg = 11.6 mg, 0.000006 kg = 6 mg, 1021 µg = 1.021 mg, and 0.31 mg = 0.31 mg. Therefore regarding to the converted measurement (mg) the above given ranking was False. And the correct ranking (11.6 mg, 0.000006 kg, 1021 µg, and 0.31 mg) is valid.

Answer 5:  1 micrometer (1 µm) equals to 10-6 m

Explanation:

One micrometer (1 µm) additionally called a micron, is equivalent to 0.000001 (10-6) m. A measurement prefix is a unit prefix that goes before an essential unit of measure to demonstrate a various or division of the unit. Each prefix has its own unit image. Power of-10 prefix multipliers encourage the induction of other, regularly increasing convenient, distance units from the meter. As such one nanometer (nm) is equivalent to 10-9 m. One Angstrom unit (symbolized Ä) is equivalent to 10-10 m, or 0.1 nm.

Answer 6:   5 is the significant digits in the measurement of 34.000 m.

Explanation:  

Significant figures are the digits of a number that are important as far as exactness or accuracy. There are three principles on deciding how many significant figures are in a number: Non-zero digits are constantly critical. A last zero or trailing zeros in the decimal part just are significant. Whereas the three most regular base units in the decimal measuring standard are the meter, gram, and liter.

Answer 7:   milli

Explanation:  

milli-(m) is a unit prefix in the decimal measuring standard by a factor of one thousandth, which is (10−3). The metric prefix implies one thousand (1,000) since 1000 milli makes one meter. So from the given estimations, milli is the littler prefix. This prefix was proposed in "1793 and received in 1795", the prefix originates from the Latin mille, signifying "one thousand" (the Latin plural is milia). And also the prefix is a piece of the International System of Units (SI).

Answer 8:   True

Explanation:  

All estimations have a level of uncertainty paying to exactness and precision. This is brought about by two factors, the impediment of the estimating instrument (deliberate blunder) and the ability of the experimenter making the estimations (arbitrary mistake). However, estimation uncertainty is a parameter that is regularly ignored. It is a significant part of the estimation that influences quality, costs, choices, and dangers.  

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A skateboarder with a mass of 60 kg moves with a force of 20 N. What is her acceleration?
Zanzabum

Explanation:

Solution,

  • Mass(m)= 60 kg
  • Force (F)= 20 N
  • Acceleration (a)= ?

We know that,

  • F=ma
  • a=F/m
  • a=20/60
  • a=0.333 m/s²

So, her acceleration is 0.333 m/s².

4 0
3 years ago
Which liquid will evaporate the fastest water salt water pepsi and gatorade?
MArishka [77]
The liquid that will evaporate the quickest would be water. 
<em>~The rest are mixtures, and have more ingrediants in them, therefore the answer should be water. (in which it has no other ingrediants in it but water itself)</em>
6 0
3 years ago
A point charge q1 = 1.0 µC is at the origin and a point charge q2 = 6.0 µC is on the x axis at x = 1 m.
iris [78.8K]

To solve this problem we will apply the concepts related to the Electrostatic Force given by Coulomb's law. This force can be mathematically described as

F = \frac{kq_1q_2}{d^2}

Here

k = Coulomb's Constant

q_{1,2} = Charge of each object

d = Distance

Our values are given as,

q_1 = 1 \mu C

q_2 = 6 \mu C

d = 1 m

k =  9*10^9 Nm^2/C^2

a) The electric force on charge q_2 is

F_{12} = \frac{ (9*10^9 Nm^2/C^2)(1*10^{-6} C)(6*10^{-6} C)}{(1 m)^2}

F_{12} = 54 mN

Force is positive i.e. repulsive

b) As the force exerted on q_2 will be equal to that act on q_1,

F_{21} = F_{12}

F_{21} = 54 mN

Force is positive i.e. repulsive

c) If q_2 = -6 \mu C, a negative sign will be introduced into the expression above i.e.

F_{12} = \frac{(9*10^9 Nm^2/C^2)(1*10^{-6} C)(-6*10^{-6} C)}{(1 m)^{2}}

F_{12} = F_{21} = -54 mN

Force is negative i.e. attractive

6 0
3 years ago
A 0.274 kg block is pushed up a frictionless ramp inclined at angle of 32° above the horizon. The push force is a constant 2.55
SpyIntel [72]

Answer:

The answer is 2,416 m/s. Let's jump in.

Explanation:

We do work with the amount of energy we can transfer to objects. According to energy theory:

W = ΔE

Also as we know W = F.x

We choose our reference point as a horizontal line at the block's rest point.<u> At the rest, block doesn't have kinetic energy</u> and <u>since it is on the reference point(as we decided) it also has no potential energy.</u>

Under the force block gains;

W = F.x → W=2,55.0,71=1,8105\frac{N}{m}

In the second position block has both kinetic and potential energy. Following the law of conservation of energy;

W = ΔE = Kinetic energy + Potantial Energy

W = ΔE = \frac{1}{2} mV^{2} + mgh

Here we can find h in the triangle i draw in the picture using sine theorem;

In a triangle \frac{a}{sinA}=\frac{b}{sinB}=\frac{c}{sinC}

In our situation

\frac{0,71}{sin90} =\frac{h}{sin32} → h=0,376

Therefore

1,8105=\frac{1}{2} 0,274V^{2} +0,274.9,81.0,376

→ V=2,416

7 0
3 years ago
Need help!
tatuchka [14]
الجواب هو الأول الجواب هو الأول
5 0
3 years ago
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