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tigry1 [53]
3 years ago
5

Assume each tick mark represents 1 cm. Calculate the total displacement from 0 if an object moves 3 cm to the left, then 7 cm to

the right, and then 6 cm to the left. The object moves cm to the left. What is the total distance the object travels? cm
Physics
2 answers:
solniwko [45]3 years ago
8 0
Assuming the positive x-axis is to the right, the displacement (a vector) can be calculated by:

0-3+7-6 = -2 cm, so the object moves 2 cm to the left. 

The total distance (a scalar quantity) can be calculated by:

0+3+7+6 = 16 cm, so the object travels a total of 16 cm. 
Alex777 [14]3 years ago
6 0

The object moves 2cm to the left.

What is the total distance the object travels? 16cm

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6 0
3 years ago
Zookeepers carry a stretcher that holds a sleeping lion. The total mass of the stretcher and lion is 175 kg. The lion's forward
ASHA 777 [7]

Answer:

350 N

Explanation:

Newton's second law:

∑F = ma

∑F = (175 kg) (2 m/s²)

∑F = 350 N

6 0
3 years ago
A student grabs a piece of paper and tears it from the middle. Which statement best explains the forces involved?
PolarNik [594]

Answer:

b. The normal force between the molecules of the paper is overcome by the contact force of the hands.

Explanation:

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3 0
3 years ago
Read 2 more answers
What changes must be done to the wire to increase its conductance.​
777dan777 [17]

Answer:

- Decreasing the resistance

- Using a shorter length

- Using a smaller area wire

Explanation:

Formula for conductance in wires is;

G = 1/R

Where;

G is conductance

R is resistance

This means that increasing the resistance leads to a larger denominator and thus a smaller conductance but to decrease the denominator means larger conductance.

Thus, to increase the conductance, we have to decrease the resistance.

Resistance here has a formula of;

R = ρL/A

Where;

ρ is resistivity

L is length of wire

A is area

Thus, to decrease the resistance, we will have to use a shorter length and smaller area of wire.

8 0
3 years ago
If 0.035pC of charge is transferred via the movement of Al3+ ions, how's many of these must be transferred in total? Please add
mr Goodwill [35]

Each Al^+^3 ion contains three extra protons. Hence, the extra charge on each  Al^+^3 = 3 \times 1.6 \times 10^-^1^9 C

Total charge = 0.035 pC

Total charge (Q) = 0.035 \times 10^-^1^2 C

Let the number of Al^+^3 ions be n.

According to question:

n \times 3 \times 1.6 \times 10^-^1^9 =0.035 \times 10^-^1^2

n = \frac{0.035 \times 10^-^1^2}{3 \times 1.6 \times 10^-^1^9}

n = 7.29167 \times 10^4

n = 72917

Hence, the total number of ions needed to be transferred is 72917

3 0
3 years ago
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