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Svetach [21]
3 years ago
12

How does increasing the distance between charged objects affect the electric force between them? the electric force increases be

cause the distance has an indirect relationship to the force. the electric force increases because the distance has a direct relationship to the force. the electric force decreases because the distance has an indirect relationship to the force. the electric force decreases because the distance has a direct relationship to the force.
Physics
2 answers:
weqwewe [10]3 years ago
6 0
According to Columb's law, when the distance between charged objects is increased then the electric force between them will decrease, this is because the two terms are inversely related. the correct option is C.
konstantin123 [22]3 years ago
3 0

the electric force decreases because the distance has an indirect relationship to the force

Explanation:

The electric force between two objects is given by

F=k \frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1 and q2 are the charges of the two objects

r is the distance between the two objects

As we can see from the formula, the magnitude of the force is inversely proportional to the square of the distance: so, when the distance between the object increases, the magnitude of the force decreases.

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PLZZZ HELP
Doss [256]

Answer/Explanation:

The weight of an object is defined as the force that is exerted due to the gravitational force.

Mathematically, it can be written as :

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We know that the value of g varies with respect to the location. At the equator, the value of g is less as compared to the poles.

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4 0
2 years ago
A migrating robin flies due north with a speed of 12 m/s relative to the air. The air moves due east with a speed of 6.7 m/s rel
mafiozo [28]

Here it is given that speed of migrating Robin is 12 m/s relative to air

so we can say that

\vec v_{ra} = 12 m/s North

so it will be

Let North direction is along Y axis and East direction is along X axis

\vec v_{ra} = 12\hat j

also it is given that speed of air is 6.7 m/s relative to ground

\vec v_a = 6.7 \hat i

now as we know by the concept of relative motion

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now by rearranging the terms

\vec v_r = \vec v_{ra} + \vec v_a

\vec v_r = 12 \hat j + 6.7 \hat i

now we need to find the speed of Robin which means we need to find the magnitude of its velocity which we found above

So here we will say

v_r = \sqrt{12^2 + 6.7^2}

v_r = 13.7 m/s

so the net speed of Robin with respect to ground will be 13.7 m/s

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3 years ago
A sprinter starts from rest, and reaches their top speed of 12 m/s in 3 seconds.
mezya [45]

Answer:

there u go :)

Explanation:

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