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Svetach [21]
3 years ago
12

How does increasing the distance between charged objects affect the electric force between them? the electric force increases be

cause the distance has an indirect relationship to the force. the electric force increases because the distance has a direct relationship to the force. the electric force decreases because the distance has an indirect relationship to the force. the electric force decreases because the distance has a direct relationship to the force.
Physics
2 answers:
weqwewe [10]3 years ago
6 0
According to Columb's law, when the distance between charged objects is increased then the electric force between them will decrease, this is because the two terms are inversely related. the correct option is C.
konstantin123 [22]3 years ago
3 0

the electric force decreases because the distance has an indirect relationship to the force

Explanation:

The electric force between two objects is given by

F=k \frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1 and q2 are the charges of the two objects

r is the distance between the two objects

As we can see from the formula, the magnitude of the force is inversely proportional to the square of the distance: so, when the distance between the object increases, the magnitude of the force decreases.

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Which of the following forces does NOT act on an object sliding down an incline plane?
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What green house gas is the most powerful absorber of radiation emitted by Earth?
dsp73

Answer:

Methane

Explanation:

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4 years ago
A 0.20-kg block on a horizontal frictionless surface is attached to an ideal massless spring whose spring constant is 360 N/m. T
Angelina_Jolie [31]

Answer:

The answer is 41,4 \frac{m}{s^{2}}

Explanation:

To understand this problem we need to visualize when block is at the equilibrium position and when the displacement is x=-2,3.10^{-2}.

According to Newton's law F=ma, if we find the force applied to the block, we can find the acceleration since we know the mass of the block.

<u>If you compress a spring by x displacement under F force, the spring's force can be found as:</u>

F_{spring} =kx

Therefore F=360\frac{N}{m} .2,3.12^{-2} =8,28N

And to find <u>acceleration</u>:

F=ma → 8,28=0,20a → a=41,4\frac{m}{s^{2}}

5 0
3 years ago
A ball is thrown up at 30m/s from the ground. What is it s maximum height?<br> How long did it take?
Rzqust [24]

<u>Answer: </u>

Maximum height reached by the ball thrown up at  30m/s is   3.06 seconds  and the height reached is  45.9 meters

<u>Explanation</u>:

Given:

Initial velocityu=30 \mathrm{m} / \mathrm{s}

To find :

maximum height =?

time taken=?

Solution:

<em>Step 1:Finding the time taken to reach the highest point</em>:

The velocity of the ball at its highest ,final velocity v=0

Using the formula,

v=u+a t

Where a is acceleration due to gravity.Its value is-9.8 m / s^{2}

Substituting the values:  

0=30+(-9.8) t

-30=(-9.8) t

t=\frac{30}{9.8}

t=3.06 \mathrm{seconds}

<em>Step 2: finding the highest point </em>

Using the formula

v^{2}-u^{2}=2 a s

where

s is the maximum highest.

Substituting values

0^{2}-(30)^{2}=2(-9.8) s

0-900=(-19.6) s

-900=(-19.6) s

s=\frac{900}{19.6}

s=45.9 \text { meters }

Result:

Thus the maximum height reached is 45.9 meters in 3.06 seconds

3 0
3 years ago
Read 2 more answers
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