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gavmur [86]
2 years ago
15

Why is a control group generally very important in an experiment?

Physics
1 answer:
Alex17521 [72]2 years ago
8 0

Answer: The control group is the part where you see what happens when you change a variable you want to study/examine. Basically, you need the control group because you need something to see what happens when you change something.

Hope this Helps! :))))

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A total distance of 4.5km. The overall journey takes 0.62h, whats the average velocity
Westkost [7]

Answer:

7.3km/hr

Explanation:

v=d/t=4.5km/0.62hrs=7.3km/hr

6 0
2 years ago
Two identical billiard balls are rolling toward each other at the same speed. What will be true after they collide head–on?
ioda
My guess is either they come to a stop when they come in contact, or one ball is going to go the opposite direction.
3 0
3 years ago
Read 2 more answers
Forces that act on an object but are not equal in size
mezya [45]
Forces that are equal in size but opposite in direction and do not cause a change in an object's movement are called balanced forces.

forces that aren't equal in size and do cause a change in movement (what it seems like you're asking for) are called UNBALANCED FORCES

so answer (in case that wasn't clear, as I'm tired) : unbalanced forces
7 0
3 years ago
During a testing process, a worker in a factory mounts a bicycle wheel on a stationary stand and applies a tangential resistive
Alex

Answer:

616.223684211 N

Explanation:

F_r = Resistive force on the wheel = 115 N

F = Force acting on sprocket

r_2 = Radius of sprocket = 4.75 cm

r_1 = Radius of wheel = 25 cm

Moment of inertia is given by

I=mr_1^2\\\Rightarrow I=1.7\times 0.25^2\\\Rightarrow I=0.10625\ kgm^2

Torque

\tau=I\alpha\\\Rightarrow \tau=0.10625\times 4.9\\\Rightarrow \tau=0.520625\ Nm

Torque is given by

\tau=Fr_2-F_rr_1\\\Rightarrow F=\dfrac{\tau+F_rr_1}{r_2}\\\Rightarrow F=\dfrac{0.520625+115\times 0.25}{0.0475}\\\Rightarrow F=616.223684211\ N

The force on the chain is 616.223684211 N

5 0
2 years ago
A 500 kg car is at rest at the top of a 72 m high hill. The car rolls to the bottom of the hill. At the bottom of the hill, the
rjkz [21]

Explanation: Solution

1.

Gravitational potential energy

U=mgh=500*9.8*50

U=245000 J

2.

Kinetic energy is present at bottom of the hill

K=(1/2)mV2=(1/2)*500*27.82

K=193210 J

3.

Work done by friction

W=193210-245000=-51790 J

3 0
2 years ago
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