The value of c, the constant of the function y = ax² + bx + c, exists -3.
<h3>What is an equation?</h3>
An equation exists as an expression that indicates the relationship between two or more numbers and variables.
Given that: y = ax² + bx + c
At point (4, 21)
21 = a(4²) + 4b + c .......(1)
At point (5, 32)
32 = a(5²) + 5b + c .........(2)
At points (6, 45)
45 = a(6²) + 6b + c .......(3)
Therefore, the value of a = 1, b = 2 and c = -3.
The value of c, the constant of the function y = ax² + bx + c, exists -3.
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Answer: the option A.
The elimination method consist is adding the two equations in a way that one variable be eliminated..
In order to do that you might have to manipulate on of the equations prior to add the two equations.
In this case, ff you multiply the second equation by - 1 you will get
- x - y = - 4
which you can add to the first equation
2x + y = 8 to eliminate the y.
Answer:
1144cm²
Approx. 1100cm²
Step-by-step explanation:
Area of rectangle=
L×B
34×20 = 680cm²
Area of semi-circle=
πr²
3.14 × (10)² = 314cm²
Area of triangle=
½b×h
b = 49 - 34 = 15
<u>2</u><u>0</u><u> </u><u>×</u><u> </u><u>1</u><u>5</u> = 150cm²
2
Area of shape =
680 + 314 + 150 = 1144cm²
approx. 1100cm²
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Six hundred and seventy six million, five hundred and fourty three thousand seven hundred and eighty nine
