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poizon [28]
3 years ago
12

A Vivelle estradiol transdermal system is a round patch measuring about 4.3 cm in diameter. Convert this dimension to inches and

millimeters.
Mathematics
1 answer:
valina [46]3 years ago
6 0

Answer:

gayerhathwthwtyjnhsrgthxfgbsghsghsdghsg

Step-by-step explanation:

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What is the length of his lower body in centimeters
dolphi86 [110]

The answer to the question is A: 0.96 centimeters

\frac{2}{5} of 1.6 is 0.64

If you subtract 0.64 from 1.6 you get 0.96, \frac{3}{5} of 1.6

5 0
4 years ago
If Sue rides 10 miles per hour on her bike, and this relationship is graphed, which ordered pair would not be on the graph?
-Dominant- [34]

Answer:

(8, 85) Would make this relationship not a function because every time you count up 1 it goes up 10 and 8 would match to 80 not 85 making 8, 85 the ordered pair would not be on the graph.


7 0
4 years ago
Which equation has a greater rate of change than the rate shown in the graph
Natali5045456 [20]

Answer:

Step-by-step explanation:

Rate of change of the graph is the slope of the line, which is ¼.

slope of y = ⅖x = ⅖ > ¼

6 0
3 years ago
Use the law of cosines to find the length of side C.
sergij07 [2.7K]

Answer:

\text{D. 36.64}

Step-by-step explanation:

The Law of Sines is given by \frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C} and works for any triangle.

Therefore, we have the proportion:

\frac{c}{\sin 41.5^{\circ}}=\frac{37}{\sin 42^{\circ}},\\\\c=\frac{37\sin 41.5^{\circ}}{\sin 42^{\circ}}=36.6399945706\approx \boxed{36.64}

8 0
3 years ago
1. The national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15. The dean of a college wants to kno
Nat2105 [25]

Answer:

We conclude that the mean IQ of her students is different from the national average.

Step-by-step explanation:

We are given that the national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15.

The dean of a college want to test whether the mean IQ of her students is different from the national average. For this, she administers IQ tests to her 144 students and calculates a mean score of 113

Let, Null Hypothesis, H_0 : \mu = 100 {means that the mean IQ of her students is same as of national average}

Alternate Hypothesis, H_1 : \mu\neq 100  {means that the mean IQ of her students is different from the national average}

(a) The test statistics that will be used here is One sample z-test statistics;

               T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ N(0,1)

where, Xbar = sample mean score = 113

              s = population standard deviation = 15

             n = sample of students = 144

So, test statistics = \frac{113-100}{\frac{15}{\sqrt{144} } }

                             = 10.4

Now, at 0.05 significance level, the z table gives critical value of 1.96. Since our test statistics is more than the critical value of z which means our test statistics will fall in the rejection region and we have sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean IQ of her students is different from the national average.

3 0
4 years ago
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