Answer:
11a+5
Step-by-step explanation:
-5a-6a-3+8
=11a+5
4.5(8 - x) + 36 = 102 - 2.5(3x + 24)
36 - 4.5x + 36 = 102 - 7.5x - 60
72 - 4.5x = 42 - 7.5x
-4.5x + 7.5x = 42 - 72
3x = - 30
x = -30/3
x = -10 <===
Hope this helps!
Answer:
X density = fXpxq and
Y" =InpXq
Now to find Y density FYpyq interms of the density of X we compare the density of X with Y"
fX = In
And PXq =pxq
Thus replacing x with y,
PXq = pyq
(a) Hence the density of Y is FYpyq
(b) at p0, fYpyq =fYp0q= 0
At 5s, FYpyq =5
The area of a right angled triangle with sides of length 9cm, 12cm and 15cm in square centimeters is 54 sq cm.
The formula to calculate the area of a right triangle is given by:
Area of Right Triangle, A = (½) × b × h square units
Where, “b” is the base (adjacent side) and “h” is the height (perpendicular side). Hence, the area of the right triangle is the product of base and height and then divide the product by 2.
We know that the hypotenuse is the longest side. So, the area of a right angled triangle will be half of the product of the remaining two sides.
Given sides of the triangle:
a=9cm
b=12cm
c=15cm
From this we know that the hypotenuse is c. Are of the triangle will be obtained by the other two sides.
∴Area =
x 9 x 12
= 54
Answer:
Step-by-step explanation:
O-ber-on'-l-a ' Od-on-tos-o'-rl-a Om-phaY-i—a Ob-e'-sT-a l Od-on-tos-per'-mum Om-phal-ob'J-um ob-e'-sum od-o'-ra* Om-phal-oc-oc'-ca ob-fus-ca'-ta od-o-ra'-ta ... oc-ul-a'-tus I ol-ig-ot'-rich-um Op-loth-e'-oa Oc'-ul-us ol-it-0'-rI-a Op-op'~on-ax ... in r12'-ler; y as I; y as i; as, w, ei, as m' in pain; an as ou- in house; g, c, and oh, ...