All categories

3 years ago

Answer plz I!!!!!!!!!!!!!!

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

8 0

Answer:

See attached

Step-by-step explanation:

The top right shows 3/4 squares shaded and 4/5 squares shaded, proving this to be the correct option.

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

★ Also please leave the rating you think I deserve (It helps other users as well as myself)

- Heather

You might be interested in

A hose dispenses 1413 cm3 of water every minute into a cone with a radius of 60 cm and a height of 150 cm.How long will it take

Sindrei [870]

<span>The question asks to find how long will it take until to fill the cone if 1413 cm^3 of water goes in it every minute. First we have to find the volume of the cone: V = 1/3 r^2 Pi * h; V = 1/3 * 60^2 * 3.14 * 150 ; V = 1/3 * 3600 * 471; V = 565,200 cm^3. If 1413 cm^3 of water goes every minute into the cone, we have to divide the volume by 1413: 565,200 : 1413 = 400. Answer: It will take 400 minutes. </span>

4 0

3 years ago

Read 2 more answers

3.95m + 34.95 > 8.95m

Alja [10]

Answer: m<6.99

Step-by-step explanation:

6 0

4 years ago

Would appreciate the help !

aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

$\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 2

$\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 3

$\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\$

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity $\sin^2(\theta)+\cos^2(\theta) = 1$ in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

3 0

3 years ago

The Slope of whats graphed

Bumek [7]

Answer:

Slope: 1/3

Step-by-step explanation:

y = 1/3 x - 2

8 0

4 years ago

What is the distance between A and B on the number line below?

gogolik [260]

Answer:

0.55

Step-by-step explanation:

all you do is subtract

4 0

3 years ago