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3 years ago

A common technique used to measure the

Physics

1 answer:

vodomira [7]3 years ago

3 0

Answer:

$K=6\ N/m$

Explanation:

<u>Force Constant of a Spring</u>

The force F applied to a spring produces a stretching distance x. These variables are linearly related as expressed by Hook's law:

$F=K.x$

If we could measure the distance a spring stretches when applying a known force, we'd be able to find the value of K. The experiment stated in the question places some mass of a known weight of 96 N that produced a stretching distance of 16 m. Knowing both variables, we can solve the above equation for K

$\displaystyle K= \frac{F}{x}=\frac{96\ N}{16\ m}=6\ N/m$

$\boxed{K=6\ N/m}$

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Answer:

Explanation:

First case

A cart speed is 0.3m/s. i.e the initial velocity is u=0.3m/s

It collide with a stationary body, then after collision the ball rebounds and move in opposite direction. This shows that the ball have a velocity after impulse let say v

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I=m(v-u)

Note, momentum is a vector quantity.

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I=m(v+u)

I=m(v+0.3)

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Second case

A cart speed is 0.3m/s. i.e the initial velocity is u=0.3m/s

It collide with a stationary body, then after collision the ball is at rest, this show that the final velocity is v=0

Then, impulse is given as the change in linear momentum of a body

Impulse =m∆v

I=m(v-u)

Note, momentum is a vector quantity.

I=m(v--u)

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In this case v=0 u=0.3m/s

I=m(0+0.3)

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If we compare impulse 1 (I¹) to impulse 2 (I²)

Subtract equation 2 from 1

We have, I¹ - I² =0.3m+mv -0.3m

I¹ - I² =mv

I¹ =mv+I²

We notice that the first impulse (I¹) is greater than second impulse (I²) by mv.

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