Greetings!
"<span>How many significant figures does 0.00340 have?"...
A significant figure is:
-A non zero number
-A zero in between non zero numbers
-Trailing zeros to the right of the decimal point
Therefore, this number has three significant figures:
3,4,0
Hope this helps.
-Benjamin</span>
Hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh
Answer:

Explanation:
As we know that magnetic field due to torroid is given as

this is approximately constant magnetic field along the axis of the torroid
now the flux linked with one coil of the torroid is given as


now total flux of N number of coils is given as

now we know that self inductance is the property of coil in which flux of the coil will link with the current in the coil
So we know that


Answer:
1.909 m
Explanation:
Length of fence = 12 m
r = Radius of circle made by the provided fence
Cirumference of a circle is given by

The circumference of the circle will be equal to the length of the fence



The radius of the fence is 1.909 m
Answer:

Explanation:
Given that
a= 8 cm (square)
A= a ² = 64 cm²
d= 4.2 mm
d₁= 2.1 mm ,K₁= 4.7
d₂=2.1 mm , K₂=2.6
We know that capacitance given as






Net capacitance



We know that stored energy given as

V= 76 V

