Answer:
25.6 m/s
Explanation:
Draw a free body diagram of the sled. There are two forces acting on the sled:
Normal force pushing perpendicular to the hill
Weight force pulling straight down
Take sum of the forces parallel to the hill:
∑F = ma
mg sin θ = ma
a = g sin θ
a = (9.8 m/s²) (sin 38.0°)
a = 6.03 m/s²
Given:
v₀ = 0 m/s
a = 6.03 m/s²
t = 4.24 s
Find: v
v = at + v₀
v = (6.03 m/s²) (4.24 s) + (0 m/s)
v = 25.6 m/s
Answer:
<em>The correct option is 1. 720 m</em>
Explanation:
<u>Projectile Motion</u>
When an object is launched in free air (no friction) with an initial speed vo at an angle
, it describes a curve which has two components: one in the horizontal direction and the other in the vertical direction. The data provided gives us the initial conditions of the survival package's launch.


The initial velocity has these components in the x and y coordinates respectively:


And we know the plane has an altitude of 600 m, so the package will reach ground level when:

The vertical distance traveled is given by:

We'll set up an equation to find the time when the package lands


Solving for t, we find only one positive solution:

The horizontal distance is:

The correct option is 1. 720 m
Explanation:
The given data is as follows.
F = 
q = 
v = 385 m/s
= 0.876
Now, we will calculate the magnitude of magnetic field as follows.
B = 
= 
=
T
= 10.65 T
Thus, we can conclude that magnitude of the magnetic field is 10.65 T.
B.. It can easily be transformed from high voltages to low voltages.
Answer:
F is non-conservative.
If F were conservative no work would be done in moving back to the original point. F dot S = W if the net distance is zero the work done is zero for a conservative force