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Makovka662 [10]
3 years ago
5

The 180 falls between which two whole numbers?

Mathematics
2 answers:
SIZIF [17.4K]3 years ago
4 0
179 and 181 are the answers
dimulka [17.4K]3 years ago
3 0
179 AND 181, THATS RIGHT BOIII
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Given: measure of angle KJ = 124°, measure of IC =38°<br><br> Find: m∠CQJ, m∠LIJ.
VLD [36.1K]

Answer:

Part 1) m

Part 2) m

Step-by-step explanation:

Part 1) Find the measure of angle CQJ

we know that

The measure of the interior angle is the semi-sum of the arcs comprising it and its opposite.

m

arc\ IK+arc\ CJ=360\°-(arc\ IC+arc\ KJ)

substitute the values

arc\ IK+arc\ CJ=360\°-(38\°+124\°)=198\°

m

Part 2) Find the measure of angle LIJ

step 1

Find the measure of angle IJL

we know that

The inscribed angle is half that of the arc it comprises.

m

substitute the values

m

step 2

Find the measure of angle ILJ

we know that

The measurement of the external angle is the semi-difference of the arcs it encompasses.

m

substitute the values

m

step 3

Find the measure of angle LIJ

Remember that the sum of the interior angles of a triangle must be equal to 180 degrees

In the triangle LIJ

m

substitute the values

m

m

3 0
3 years ago
What numbers fall between 4.7 and 4.8 on a number line
SVEN [57.7K]

Answer:

4.71, 4.72, 4.73, 4.74, 4.75, 4.76,4.77, 4.78, and 4.79

Step-by-step explanation:

all you need to do is move into hundredths and you need to know that there are 10 hundredths between 2 tenths.

3 0
3 years ago
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How do you write 415 thousandths
Greeley [361]
415 thousandths is written out 0.415
8 0
3 years ago
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Add the two expressions.<br><br> −2.4n−3 and −7.8n+2
Sphinxa [80]

Answer:

-10.2n - 1

Step-by-step explanation:

We have two expressions in variable n and we have to add the two expressions.

An important thing to note is that only like terms can be added. i.e. the term with "n" can only be added or subtracted to the term with "n". Similarly a constant can only be added or subtracted to a constant.

(-2.4n-3)+(-7.8n+2)\\=-2.4n-3-7.8n+2\\=-2.4n-7.8n-3+2\\=-10.2n-1

Thus, the two given expressions add up to -10.2n - 1

4 0
3 years ago
Solve sin 0 + 1 = cos20 on the interval 0 ≤ 0 &lt; 2pi. Show work please!
yan [13]

Answer:

\theta=\frac{\pi}{2},\frac{3\pi}{2}\frac{2\pi}{3}\frac{4\pi}{3}

Step-by-step explanation:

You need 2 things in order to solve this equation:  a trig identity sheet and a unit circle.

You will find when you look on your trig identity sheet that

cos(2\theta)=1-2sin^2(\theta)

so we will make that replacement, getting everything in terms of sin:

sin(\theta)+1=1-2sin^2(\theta)

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

2sin^2(\theta)+sin(\theta)=0

We can factor out the sin(theta), since it's common in both terms:

sin(\theta)(2sin(\theta)+1)=0

Because of the Zero Product Property, either

sin(\theta)=0 or

2sin(\theta)+1=0

Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi.  They are:

\theta=\frac{\pi}{2},\frac{3\pi}{2}

The next equation needs to first be solved for sin(theta):

2sin(\theta)+1=0 so

2sin(\theta)=-1 and

sin(\theta)=-\frac{1}{2}

Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval.  They are:

\theta=\frac{2\pi}{3},\frac{4\pi}{3}

7 0
3 years ago
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