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3 years ago

This question, please answer it

Mathematics

2 answers:

zzz [600]3 years ago

6 0

I want to help, what is the question? Haha

kobusy [5.1K]3 years ago

5 0

I don’t really see a question-

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If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf

jonny [76]

With the curve $C$ parameterized by

$C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k$

with $0\le t\le\dfrac\pi2$ , and given the vector field

$\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k$

the work done by $\mathbf f$ on a particle moving on along $C$ is given by the line integral

$\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt$

where

$\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt$

The integral is then

$\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt$
$=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t$
$=269$

6 0

3 years ago

while swimming a 2km race, Adam changes from breaststroke to butterfly every 200m. How many times does he switch strokes during

aleksley [76]

in the first half he would have swam 1 km. there are 1000m in a km so 1000/200=5 so he swam the first 200 fly, then a 200 breast, then a 200 fly again, then another 200 breast the finish the first 1 km with a 200 fly. so we switched strokes 4 times.

PS i wouldn't recommend doing a 2 km swim fly and breast

8 0

3 years ago

Read 2 more answers

What is the common ratio of 40,12,3.6

slava [35]

Answer:

0.3

Step-by-step explanation:

Divide the second term (12) with the first term (40), and you'll get 0.3

This is correct because you get the terms in the correct order when multiplying:
(First term: 40. Common ratio: 0.3)
40 x 0.3 = 12
12 x 0.3 = 3.6

40, 12, 3.6

3 0

2 years ago

Please help me solve this whole problem!

Dvinal [7]

I’m not good at math srry but hope someone answers the is for you

3 0

2 years ago

Read 2 more answers

A playstation 5 is $900 and costs $50 per game. A xbox is $400 and costs $60 per game. How many games will it take for both cons

belka [17]

Answer:

It would take a PlayStation 5 and 2 games to equal an Xbox and 10 games.

Step-by-step explanation:

I made a list that increase in the increments of the game price.

Something like this:

900—400~consoles alone

950—460~1 game

1000–520~2 games

1050—580~3 games

1100—640~4 games

1150—700~5 games

1200—760~6 games

1250—820~7 games

1300—880~8 games

1350—940~9 games

1400—1000~10 games

Left side is PlayStation 5 and right side is Xbox. The first row is the price of the consoles alone and then each row after that is the price of the console with an additional game. As you can see, the third row down on the left, the PlayStation 5 with 2 games is $1,000. If you look at the eleventh row on the right, you can see that Xbox with 10 games is also $1,000

3 0

2 years ago