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Alex Ar [27]
3 years ago
11

I seriously need help

Mathematics
1 answer:
777dan777 [17]3 years ago
8 0

Answer:

x(t) = - 5 + 6t and y(t) = 3 - 9t

Step-by-step explanation:

We have to identify the set of parametric equations over the interval 0 ≤ t ≤ 1 defines the line segment with initial point (-5,3) and terminal point (1,-6).

Now, put t = 0 in the sets of parametric equations in the options so that the x value is - 5 and the y-value is 3.

x(t) = - 5 + t and y(t) = 3 - 6t and  

x(t) = - 5 + 6t and y(t) = 3 - 9t

Both of the above sets of equations satisfy this above conditions.

Now, put t = 1 in both the above sets of parametric equations and check where we get x = 1 and y = -6.

So, the only set, x(t) = - 5 + 6t and y(t) = 3 - 9t  satisfies this condition.

Therefore, this is the answer. (Answer)

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Answer:

Part A

x + y ≤ 460

2.5·x + 1.25·y ≥ 600

Part B

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Step-by-step explanation:

The given parameters are;

The selling price of a can of lemonade = $2.50

The selling price for each bottle of water = $1.25

The amount the club needs to raise to cover the cost of renting costumes, A = $600

The maximum acceptable cans and bottles = 460

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Let 'x', represent the number of cans of lemonade accepted by the students, and let 'y' represent the number of bottles of water accepted, we have;

The situation can be represented by the following system of inequalities

x + y ≤ 460

2.5·x + 1.25·y ≥ 600

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The number of cans of lemonade sold, x = 144

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2.5 × 144 + 1.25·y ≥ 600

1.25·y ≥ 600 - 2.5 × 144 = 240

1.25·y ≥ 240

y ≥ 240/1.25 = 192

y ≥ 192

The least number of bottles of water that must be sold to cover the cost of renting costumes, y = 192 bottles

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