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3 years ago

8

A lens is used to make an image of magnification -1.50. The image is 30.0 cm from the lens. What is the object’s distance (unit=

cm)?

1 answer:

alex41 [277]3 years ago

8 0

Answer: Object distance is : 20cm

Explanation:

Given the following :

Magnification (m) = - 1.50

Image Distance from lens (v) = 30cm

Calculate the object distance (u) :

Recall:

Magnification = - [image distance (v) / object distance (u)]

Therefore, Inputting our values :

-1.50 = - (30 / u)

1.50 * u = 30

u = 30 / 1.50

u = 20 cm

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Murrr4er [49]

Answer:

15.64 KN

Explanation:

mass of the elevator cab with a single occupant= 2300 kg

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acceleration of the coin relative to the cab in the opposite direction of motion of cab so we can consider it as a= -6.80 m/s^2

The acceleration of elevator cab relative to the ground $a_{cg}$

now we can say that

$a_{ce} +a_{eg} =a_{cg}$

=-6.80+ a_{eg}= -9.8

[tex]a_{eg}=-9.8+6.80=-3.8

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3 years ago

During a sunny afternoon, the sun suddenly seems much less bright than usual. The daylight seems much less intense, as if there

Tatiana [17]

Answer:

D). A sudden change in temperature increased the density of the atmosphere.

Explanation:

The claim that can be made and supported with evidence regarding the temporary decrease in light would be 'a sudden change in temperature will increase the density of the atmosphere.' <u>As the temperature increases, the molecules in the atmosphere begin to move fastly which causes a decrease in atmosphere density while it increases with the fall in temperature. As a result, the intensity of sunlight gets affected due to molecules being heavier and floating in the atmosphere</u>. Thus, <u>option D</u> is the correct answer.

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3 years ago

Assume the average value of the vertical component of Earth's magnetic field is 42 μT (downward) in some region that has an area

Oliga [24]

Answer:

The net magnetic flux through the rest of Earth's surface is $5.782\times10^{-2}\ T$

Explanation:

Given that,

Magnetic field = 42 μT

Area $A=3.71\times10^{5}\ km^2$

$A=3.71\times10^{11}\ m^2$

We need to calculate the flux per unit area

$flux\ per\ unit\ area=\dfrac{42\times10^{-6}}{3.71\times10^{11}}$

$flux\ per\ unit\ area=1.132\times10^{-16}\ T/m^2$

We need to calculate the total earth's surface area

$A'=4\pi r^2$

$A'=4\times\pi\times(6.3781\times10^{6})^2$

$A'=5.1120\times10^{14}\ m^2$

We need to calculate the rest of earth's area

$A''=A-A'$

Put the value into the formula

$A''=5.1120\times10^{14}-3.71\times10^{11}$

$A''=5.10829\times10^{14}\ m^2$

We need to calculate the net magnetic flux through the rest of Earth's surface

$B'=5.10829\times10^{14}\times1.132\times10^{-16}$

$B'=5.782\times10^{-2}\ T$

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4 years ago

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Answer:

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We have,

Mass of ink, m = 5 grams = 0.005 kg

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We need to find the kinetic energy of the solution of water and ink. Kinetic energy is associated with the motion of an object. Its formula is given by :

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dem82 [27]

Explanation:

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3 years ago