I think it is 4 cm because if you look hard enough and work the problem the number pops in you head. Lol
Nitrogen gas has a molar mass of about 28.0134 g/mol. Then we have a starting amount of
(42 g) / (28.0134 g/mol) ≈ 1.4993 mol
of N₂.
At standard temperature and pressure, one mole of an ideal gas occupies a volume of about 22.4 L. Then 42 g, or 1.4993 mol, of N₂ takes up
(1.4993 mol) × (22.4 L/mol) ≈ 33.6 L
Answer : The time taken for the concentration will be, 7.98 seconds
Explanation :
First order reaction : A reaction is said to be of first order if the rate is depend on the concentration of the reactants, that means the rate depends linearly on one reactant concentration.
Expression for rate law for first order kinetics is given by :
![k=\frac{2.303}{t}\log\frac{[A]_o}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%5Cfrac%7B%5BA%5D_o%7D%7B%5BA%5D%7D)
where,
k = rate constant = 
t = time taken for the process = ?
= initial concentration = 0.860 M
= concentration after time 't' = 0.260 M
Now put all the given values in above equation, we get:


Therefore, the time taken for the concentration will be, 7.98 seconds
Answer:
Different street blocks are different lengths, so it won't be possible to answer this.