So we are given the mean and the s.d.. The mean is 100 and the sd is 15 and we are trying the select a random person who has an I.Q. of over 126. So our first step is to use our z-score equation:
z = x - mean/s.d.
where x is our I.Q. we are looking for
So we plug in our numbers and we get:
126-100/15 = 1.73333
Next we look at our z-score table for our P-value and I got 0.9582
Since we are looking for a person who has an I.Q. higher than 126, we do 1 - P. So we get
1 - 0.9582 = 0.0418
Since they are asking for the probability, we multiply our P-value by 100, and we get
0.0418 * 100 = 4.18%
And our answer is
4.18% that a randomly selected person has an I.Q. above 126
Hopes this helps!
Answer:
C. 
Step-by-step explanation:
Height = 4
Length = 6
Breadth = 7
Note : We were asked to find volume of the cuboid
Since, it has a base in the shape of a right angle triangle , we need to find the Area of the trapezium before calculating the total volume.
Step 1
Find the area of the trapezium
Area of a trapezium = 



Step 2
Calculate the volume of the cuboid
Volume of a cuboid =length× breadth × height
In this case , the volume will be our length × Area of a trapezium
V= 6 × 22
V = 
Answer:
(a) The amount of ice cream increase as temperature increases
(b)
--- equation
--- y intercept
--- slope
Step-by-step explanation:
Given
See attachment for graph
Solving (a): The relationship between the variables
From the attached graph, the dots on the graph increases towards up-right direction. This implies that there is a positive correlation between the variables.
In other words;
The amount of ice cream increase as temperature increases
Solving (b): The line of best fit
First, we draw a line through the points (the line should have almost equal points on both sides; see attachment 2).
From (2), we select any 2 points on the line:


The slope (m) is:




So, the line of best fit is:

Substitute known values:



The y-intercept is when 
So, we have:



Let the weight of soymeal be s, and let the weight of cornmeal be c.
You need a total of 280 lb, so that gives us one equation.
s + c = 280
Now we use the protein to write another equation.
The protein in s lb of soymeal is 0.14s.
The protein in c lb of cornmeal is 0.07c.
The protein in 280 lb of 0.09% protein mix is 0.09(280).
This gives us a second equation.
0.14s + 0.07c = 0.09(280)
Now we solve the two equations as a system of equations.
s + c = 280
0.14s + 0.07c = 0.09(280)
Solve the first equation for s and plug in tot eh second equation.
s = 280 - c
0.14(280 - c) + 0.07c = 25.2
39.2 - 0.14c + 0.07c = 25.2
-0.07c = -14
c = 200
Now we substitute c = 200 in the first equation to find s.
s + 200 = 280
s = 80
Answer: 200 lb of soymeal and 80 lb of cornmeal
The answer is y=-1/2x + 5/8