It’s -3,-2 hope thiisssss helpsssss
Answer:
6580cm
Step-by-step explanation:
The answer is 6580cm because....
Step one First let's figure out what the smaller shape's volume is. To do so we need to multiply ( LxWxH ) so 6x5x? it does not list what the height is so we know it has the same height as the larger shape and it's height is 14cm so we will use 14cm. 6x5x14=420cm
Step two Now lets find the Volume of the larger shape. So lets do LxWxH so Lx?x14 it does not give us the length so we need to add up all of the numbers along the line. We got 7cm then 5 from the bottom of the smaller shape and 10cm. all ads up to 22cm so 20x22x14=6160
Finally we add up the following shapes Volume which are 6160+420=6580cm
y = x^2 -4x
x = -1
y = (-1)^2 - 4×-1=1+4 = 5
x= 0
y = (0)^2 - 4×0 = 0
x = 1
y = 1^2 -4×1 = 1-4 = -3
x = 2
y = 2^2 -4×2 = 4-8 = -4
x=3
y = 3^2 - 4×3 = 9-12 = -3
x = 4
y = 4^2 - 4×4 = 16 - 16 = 0
now 2nd equation
y = 2x^2 + x
x = -2
y = 2 (-2)^2 + (-2)= 8-2 = 6
x = -1
y = 2 (-1)^2+(-1)= 2-1 = 1
x = 0
y = 2(0)^2 +0 = 0
x = 1
y = 2 (1)^2 + 1 = 3
x = 2
y = 2(2)^2+2= 8 + 2 = 10
The distance between starting and ending point is 34 miles.
Step-by-step explanation:
Given,
Car moves 16 miles to north then 30 mile to east.
It forms a right angle triangle.
The straight line distance from starting to ending point represents hypotenuse.
To find the distance between starting and ending point.
Formula
By <em>Pythagoras theorem,</em>
h² = b²+l² where h is the hypotenuse, b is base and l is the another side.
Taking, b=16 and l=30 we get,
h² = 16²+30²
or, h = 
or, h =
= 34
Hence,
The distance between starting and ending point is 34 miles.
Nine is in the tenths place