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Kruka [31]
3 years ago
9

e do loop differs from the while loop in that a. the while loop will always execute the body of the loop at least once b. the do

loop will always execute the body of the loop at least once c. the do loop will continue to loop while the condition in its while statement is false and the while loop will continue to loop while the condition in its while statement is true d. the while loop will continue to loop while the condition in its while statement is false and the do loop will continue to loop while the condition in its while statement is true e. None of these; there is no difference between the two types of loops
Computers and Technology
1 answer:
cluponka [151]3 years ago
6 0

Answer:

b. the do loop will always execute the body of the loop at least once

Explanation:

The do loop will always execute the body of the loop at least once becuase it is an exit loop, that means the condition is always checked at the end, where as while loop execute hte body of the loop zero times as it is an entry loop and the condition will be checked prior to the execution of body of the loop.

do loop structure is as shown below

do{

}while()

So it executes the block atleast once and then checks the condition

Hence, the do loop will always execute the body of the loop at least once.

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The router can deliver packets directly over interfaces 0 and 1 or it can forward packets to Routers R2, R3, or R4. Describe wha
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Following are the solution to this question:

Explanation:

In point A:

It applies the AND operation with the subnet-mask that is  

=128.96.39.00001010 \ \ AND \ \ 255.255.255.10000000 \\\\= 128.96.39.0000000 \\\\= 128.96.39.0 \\\

This corresponds to a 128.96.39.0 subnet. This is why the router sent the packet to 0.

In point B:  

It applies the AND operation with the subnet-mask that is 255.255.255.128

= 128.96.40.00001100\  AND \ 255.255.255.10000000 \\\\ = 128.96.40.0000000\\\\= 128.96.40.0

This suits the 128.96.40.0 subnet. The router then sent R2 to the packet. The packet.

In point C:  

It  applies the AND operation with the subnet-mask that is 255.255.255.128

=128.96.40.10010111 \ AND \ 255.255.255.10000000 \\\\= 128.96.40.1000000\\\\= 128.96.40.128

It  applies the AND operation with the subnet-mask  that is 255.255.255.192

= 128.96.40.10010111 \ AND \ 255.255.255.11000000 \\\\= 128.96.40.1000000 \\\\= 128.96.40.128\\

All of the matches of its sublinks above.  

Its default R4 router was therefore sent to the router by router.

In point D:

It  applies the AND operation with the subnet-mask  that is 255.255.255.192

= 192.4.153.00010001 \ AND \ 255.255.255.11000000\\\\ = 192.4.153.0000000 \\\\= 192.4.153.0 \\\\

It matches the 192.4.153.0 subnet. It router has sent packet to R3 then.

In point E:

It  applies the AND operation with the subnet-mask  that is 255.255.255.128

= 192.4.153.01011010\  AND \ 255.255.255.10000000 \\\\= 192.4.153.0000000 \\\\= 192.4.153.0

There, neither of the subnet inputs correlate with the ip address with the same subnet mask.

It  applies the AND operation with the subnet-mask  that is 255.255.255.192

=192.4.153.01011010\ AND \ 255.255.255.11000000 \\\\ = 192.4.153.0100000 \\\\= 192.4.153.64

It does not correlate to the subnet entries for same subnet mask, and therefore neither of the entries matches their corresponding ip address entries.  

Mask of the subnet.  That packet would therefore be sent to the default R4 router by the router.

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2 years ago
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