Letter A is the answer because
4y = 15 - 3x
so y = 15/4 -3x/4
Answer:
B
Step-by-step explanation:
The chi-squared test statistic will be 3.11. The test statistic is contrasted with a predicted value based on the Chi-square distribution.
<h3>What is the chi-squared test statistic?</h3>
Finding the squared difference between the actual and anticipated data values, then dividing that difference by the expected data values, constitutes the test statistic.
The formula for the chi-squared test statistic is;
Where,
is the observed value
is the expected value
The chi-square test statics is;
Hence, the chi-squared test statistic will be 3.11.
To learn more about the chi-squared test statistic refer;
brainly.com/question/14082240
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Answer:
The answer is 1,550
Step-by-step explanation:
First you find the area of the rectangle 1
Area = ab
=(21 in) (17in)
=357 sq in.
this will be the same for rectangle 3 = 357 sq. in.
next find the area of rectangle 2
area=ac
=(21 in) (11 in)
=231 sq in.
this will be the same for rectangle 4 = 231 sq. in.
next find the area of rectangle 5
area = bc
=(17 in) (11 in.)
=187 sq. in
this will be the same for rectangle 6 = 187 sq. in.
Next add all areas together
Total surface area = 2(ac) + 2(ab) + 2(bc)
= 2(231) sq in. + 2(357) sq in. + 2(187) sq. in
= 462 + 174+ 374
= 1550 sq. in
Answer:
1. y= 3x+7
2.y=1/2 x -1
Step-by-step explanation:
1.
Parallel lines have the same gradient.In the equation given,
y= 3x+5 , the slope is 3
So now, you find the equation of a line passing through point (-1,4) with m=3
m=Δ y/Δx
3= y-4/ x--1
3= y-4 /x+1
3(x+1) = y-4
3x+3 =y-4
3x+3+4=y
⇒⇒ y= 3x+7 is the equation.
2.
Two lines that are perpendicular to each other have the product of their slopes to be -1
Given equation to be y= -2x +8 then, m₁ = -2
Finding m₂ will be;
m₁ *m₂ = -1
-2 * m₂ = -1
-2 m₂ = -1
m₂ = -1/-2 = 1/2
So writing the equation of the perpendicular line with m₂ =1/2 , point (-4,-3)
will be;
m=Δy/Δx
1/2=y--3/x--4
1/2 = y+3/x+4
x+4 = 2( y+3)
x+4 = 2(y+3)
x+4 =2y+6
x+4-6=2y
x-2=2y
x/2 -2/2=y
y=1/2 x -1 is the equation.
