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IgorLugansk [536]
3 years ago
12

a coin is taken at random froma purse that contains one penny, 2 nickels, 4 dimes, and 3 quarters. let x be the value of the dra

wn coin. find the average value of x if we repeat the first draw many times
Mathematics
1 answer:
algol [13]3 years ago
6 0

Answer:

x = 12.6 pennies

Step-by-step explanation:

total number of coins = 1 + 2+ 4 + 3 = 10 coins

P(penny) =\dfrac{1}{10}

P(nickels) =\dfrac{2}{10}

P(dimes) =\dfrac{4}{10}

P(quarters) =\dfrac{3}{10}

hence average value of the coin

x = Penny x P(Penny) + nickel x P(nickel) + dimes x P(dimes) + quarters x P(quarters)

nickels  = 5 pennies dimes = 10 ; and quarters = 25 pennies

x = 1 \times \dfrac{1}{10} + 5\times \dfrac{2}{10} +10\times \dfrac{4}{10} +  25\times \dfrac{3}{10}

x = 0.1 + 1 + 4 + 7.5

x = 12.6 pennies

hence, the average pennies for the first draw is equal to x = 12.6 pennies

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viktelen [127]

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(5,-6) is a solution

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Given

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Required

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Hello from MrBillDoesMath!

Answer:

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Discussion:

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Regards,  

MrB

P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!


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