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IgorLugansk [536]
3 years ago
12

a coin is taken at random froma purse that contains one penny, 2 nickels, 4 dimes, and 3 quarters. let x be the value of the dra

wn coin. find the average value of x if we repeat the first draw many times
Mathematics
1 answer:
algol [13]3 years ago
6 0

Answer:

x = 12.6 pennies

Step-by-step explanation:

total number of coins = 1 + 2+ 4 + 3 = 10 coins

P(penny) =\dfrac{1}{10}

P(nickels) =\dfrac{2}{10}

P(dimes) =\dfrac{4}{10}

P(quarters) =\dfrac{3}{10}

hence average value of the coin

x = Penny x P(Penny) + nickel x P(nickel) + dimes x P(dimes) + quarters x P(quarters)

nickels  = 5 pennies dimes = 10 ; and quarters = 25 pennies

x = 1 \times \dfrac{1}{10} + 5\times \dfrac{2}{10} +10\times \dfrac{4}{10} +  25\times \dfrac{3}{10}

x = 0.1 + 1 + 4 + 7.5

x = 12.6 pennies

hence, the average pennies for the first draw is equal to x = 12.6 pennies

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Which steps would you use to solve this equation? Check all that apply p + 7 = 12
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              - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}

           Which steps would you use to solve this equation? p+7=12

\large\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}

We can solve this equation in one step only, and this is the step:-

         Subtract 7 from both sides

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<h3>Good luck.</h3>

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2 years ago
An 5kg object is 6 meters what is the potential energy
AVprozaik [17]

Potential Energy of an object of 5kg which is 6 meters in height is 294 Joules.

Step-by-step explanation:

We are given:

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Height = h= 6 meters

Potential Energy = ?

The formula used to find Potential Energy is:

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Putting the given values of mass and height, and g=9.8 m/s^2

Potential Energy = 5*9.8*6\\Potential Energy = 294 Joules

So, Potential Energy of an object of 5kg which is 6 meters in height is 294 Joules.

Keywords: Potential Energy

Learn more about Potential Energy at:

  • brainly.com/question/6013189
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  • brainly.com/question/1198647

#learnwithBrainly

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