Using the knowledge in computational language in LC-3 Assembly it is possible to write a code that replaces the value in R0 with its absolute value
<h3>Writting the code </h3>
.ORIG x0200
START
AND R0, R0, #0 ; copy R0 to itself to set the condition codes based on R0;
; i.e performing addition operation with Zero option to set the flags
BRzp DONE ; if R0 is NON-NEGATIVE, skip the negation (already correct);
; Branch to DONE if number is poistive
NOT R0, R0 ; R0 is negative, so negate it i.e taking 2's complement
ADD R0, R0, #1 ; R0 = -R0 is performed successfully
DONE BR START
.END
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Answer:
The correct Answer is 0.0571
Explanation:
53% of U.S. households have a PCs.
So, P(Having personal computer) = p = 0.53
Sample size(n) = 250
np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10
So, we can just estimate binomial distribution to normal distribution
Mean of proportion(p) = 0.53
Standard error of proportion(SE) =
=
= 0.0316
For x = 120, sample proportion(p) =
=
= 0.48
So, likelihood that fewer than 120 have a PC
= P(x < 120)
= P( p^ < 0.48 )
= P(z <
) (z=
)
= P(z < -1.58)
= 0.0571 ( From normal table )
Answer:
settings>Accessibility>Touch>AssistiveTouch>Turn off
Explanation: