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3 years ago

Why is an ISA unlikely to change between successive generations of microarchitectures

Computers and Technology

1 answer:

QveST [7]3 years ago

4 0

Someone answer this because I need to know as well
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A computer system has 9,850 processes and 172 of them were suspended while 276 of them were terminated. Explain why some of the

Mrrafil [7]

Answer:

Check below for answers and explanations.

Explanation:

The major reasons why computer processes are suspended or terminated are:

1. When there is insufficient memory for successful completion of the process

2. When there's an unauthorized access of any of the computer resources by the process.

It is possible that some processes are terminated why some are suspended because, when the system runs out of memory, the running processes are put on hold until the system is able to create free memory space for the completion of the process. In this case the process is suspended. But if the system cannot provide enough space for the process, the process is terminated.

In the example provided in this exercise, some of the processes were suspended because the system wants to create free memory space for their completion while others are terminated either because the available space is not sufficient for their completion or they want to access an unauthorized resources on the system.

4 0

3 years ago

Making phone calls with a public box

AfilCa [17]

Answer:

ja ok it is so eassssy.........................

8 0

3 years ago

Each codec is stored within a file called a(n) ____ file.

frutty [35]

Im like 90% sure its a container file

5 0

3 years ago

The study of how to design software, solve problems such as computer security threats, or come up with better ways of handling d

Gnom [1K]

Computer engineering

3 0

3 years ago

A router receives a packet and determines the outbound link for the packet. When the packet arrives, 2/3 of one other packet is

vlada-n [284]

Answer:

Queuing Delay is 0.08 seconds

Explanation:

The answer follows a formula that is relatively easy to use and is detailed below.

Queuing Delay = [(L - x) + (nL)] / R

where,

L is packet length given as 3,000 bytes

x is the currently transmitted packet given as 2/3 * 3,000 = 2,000

n is the number of packets waiting in the Que given as 5

R is the rate of transmission given as 4 Mbps (4 * 10^6 Bps)

We can simply plug in the above information in the equation for computing Queuing Delay.

Lets take the numerator first which would be [(3000 - 2000) + (5 * 3000)]

The numerator would be 16000 bytes. These are being transmitted at 4Mbps. So, 16000*4*5 = 320,000 "bits"

Queuing Delay= 320,000/4000000

Queuing Delay = 0.08 seconds.

As we can see, the formula is quite intuitive to use. You are simply taking the number of packets to be transmitting, incorporating the partially transmitted packet, multiplying by the number of packets and the rate of transmission and then dividing the product by the rate of transmission to compute what the delay in the Que is.

6 0

3 years ago