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Svetradugi [14.3K]
3 years ago
11

Why is an ISA unlikely to change between successive generations of microarchitectures

Computers and Technology
1 answer:
QveST [7]3 years ago
4 0
Someone answer this because I need to know as well
\
You might be interested in
Construct sequence using a specified number of integers within a range. The sequence must be strictly increasing at first and th
natulia [17]

Answer:

Explanation:

The following code is written in Java. It first creates a function that takes in the three parameters to create the sequence, if the sequence is valid it returns the created sequence, otherwise it prints -1 and returns an empty array. The second function called compareSequences takes in to sequences as parameters and compares them, printing out the winner. A test case has been provided in the main method and the output can be seen in the image below.

import java.util.Arrays;

class Brainly {

   public static void main(String[] args) {

       int[] seq1 = createSequence(5, 4, 2);

       int[] seq2 = createSequence(5, 3, 3);

       System.out.println("Winner: " + Arrays.toString(compareSequences(seq1, seq2)));

   }

   public static int[] createSequence(int num, int upperEnd, int lowerEnd) {

       int[] myArray = new int[num];

       int middle = (int) Math.floor(num/2.0);

       myArray[0] = upperEnd;

       myArray[num-1] = lowerEnd;

       int currentValue = upperEnd;

       for (int i = 1; i < num-1; i++) {

           if (i <= middle) {

               myArray[i] = currentValue + 1;

               currentValue += 1;

           } else {

               myArray[i] = currentValue - 1;

               currentValue += 1;

           }

       }

       System.out.println(Arrays.toString(myArray));

       if (myArray[num-2] < lowerEnd) {

           System.out.println("-1");

           int[] empty = {};

           return empty;

       } else {

           return myArray;

       }

   }

   public static int[] compareSequences(int[] seq1, int[] seq2) {

       int lowestLength;

       if (seq1.length > seq2.length) {

           lowestLength = seq2.length;

       } else {

           lowestLength = seq1.length;

       }

       for (int i = 0; i < lowestLength; i++) {

           if (seq1[i] > seq2[i]) {

               return seq1;

           } else if (seq1[i] < seq2[i]) {

               return seq2;

           }

       }

       if (seq1.length > seq2.length) {

           return seq1;

       } else {

           return seq2;

       }

   }

}

7 0
3 years ago
Write a function called mul_time that takes a Time_Elapsed object and a number and returns a new Time_Elapsed object that contai
lisov135 [29]

# Write a function called mul_time that takes a Time object and a number and

# returns a new Time object that contains the product of the original Time and

# the number.

# Then use mul_time to write a function that takes a Time object that

# represents the finishing time in a race, and a number that represents the

# distance, and returns a Time object that represents the average pace (time

# per mile).

# Current Status: Complete

class Time(object):

   """ represents the time of day.

   attributes: hour, minute, second"""

time = Time()

time.hour = 3

time.minute = 0

time.second = 0

def time_to_int(time):

   minutes = time.hour * 60 + time.minute

   seconds = minutes * 60 + time.second

   return seconds

def int_to_time(seconds):

   new_time = Time()

   minutes, new_time.second = divmod(seconds, 60)

   time.hour, time.minute = divmod(minutes, 60)

   return time

def mul_time(time, multicand):

   time_int = time_to_int(time) * multicand

   new_time = int_to_time(time_int)

   if new_time.hour > 12:

       new_time.hour = new_time.hour % 12

#    print ("New time is: %.2d:%.2d:%.2d"

#    % (new_time.hour, new_time.minute, new_time.second))

   return new_time

# mul_time(time, 2)

def race_stats(time, distance):

   print ("The finish time was %.2d:%.2d:%.2d"

         % (time.hour, time.minute, time.second))

   print "The distance was %d miles" % (distance)

   average = mul_time(time, (1.0 / distance))

   print ("The average is: %.2d:%.2d:%.2d per mile"

         % (average.hour, average.minute, average.second))

race_stats(time, 3)

7 0
2 years ago
How to make a website
hjlf

Answer:

You need an email and a job and to be over 18 for business ones or a legal gaurdian if you have none then ur hecced uwu :333

8 0
3 years ago
Read 2 more answers
Write a function that will sum all of the numbers in a list, ignoring the non-numbers. The function should takes one parameter:
olasank [31]

In python 3.8:

def func(value_list):

   lst = [x for x in value_list if type(x) == int or type(x) == float]

   return sum(lst)

print(func(["h", "w", 32, 342.23, 'j']))

This is one solution using list comprehensions. I prefer this route because the code is concise.

def func(value_list):

   total = 0

   for x in value_list:

       if type(x) == int or type(x) == float:

           total += x

   return total

print(func(["h", "w", 32, 342.23, 'j']))

This is the way as described in your problem.

3 0
3 years ago
What is not true of efs
Lemur [1.5K]

Answer:

EFS cannot store files encrypted.

Explanation:

EFS) is a feature introduced in version 3.0 of NTFS that provides filesystem-level encryption. EFS is useful for mobile computer users, whose computer are subject to physical theft, and for storing highly sensitive data. Encryption itself is the method where the information is converted into secret code that hides the information's true meaning. (EFS) is used to encrypt files and folders. EFS is easy to use, with nothing more than a check box in a file’s properties. It is not fully supported on Windows 7 Starter, Windows 7 Home Basic, and Windows 7 Home Premium!

3 0
3 years ago
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