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kotykmax [81]
3 years ago
15

Please help 15 points x2≥−4

Mathematics
1 answer:
Nutka1998 [239]3 years ago
6 0

Answer:

Solve for  

x

by simplifying both sides of the inequality, then isolating the variable.

Step-by-step explanation:

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Complete the equation of the line through (−8,8), and (1,-10 ). Use exact numbers. Help me please my dog just died and I want to
katrin2010 [14]

Answer: (Mayadc821 wrote this anwser check theyre account for more)

Since you know the x and y values, you just have to plug these into the linear slope-intercept equation:

y = mx + b

-10 = m(1) + b

m + b = -10

b = -10 - m

Now that we have a value for b, we can plug this into the other equation:

8 = m(-8) + b

8 = -8m + (-10 - m)

8 = -9m -10

18 = -9m

m = -2

Now that we know what m is equal to, we can plug this into our first equation to get an answer for b:

b = -10 - m

b = -10 -(-2)

b = -10 + 2

b = -8

Our final equation is y = -2x - 8

6 0
3 years ago
I need help on this ASAP
klemol [59]

Answer:

The answer is C.

Step-by-step explanation:

When you add the same negative and positive number it's 0.

For Example:

-5 + 5= 0

6 0
2 years ago
Brian is riding his bike. He biked a distance of 14 miles at a rate of 14 miles per hour. Rearrange the distance formula, d = rt
Stells [14]

Answer:

C. 60 minutes

Step-by-step explanation:

if Brian biked 14 miles in 1 hour and 1 hour = 60 minutes then the answer is 60 minutes. hope this helps

5 0
3 years ago
I need help , plz help me and the question just like other one I think ?
ad-work [718]

Answer:

formula = LxWxH

substitute = L = 10 in  W = 7in H = 14 in

simply = 980

Step-by-step explanation:

since its a rectangle you multiply all the sides together.

4 0
3 years ago
The radius of a circle is changing at the rate of 1/π inches per second. At what rate, in square inches per second, is the circl
MAXImum [283]

Answer:

10 square inches per second.

Step-by-step explanation:

The radius of the circle is given by the equation:

r(t) = (1/π  in/s)*t

Where time in seconds.

Remember that the area of a circle of radius R is written as:

A = π*R^2

Then the area of our circle will be:

A(t) = π*( (1/π  in/s)*t)^2 = π*(1/π  in/s)^2*(t)^2

Now we want to find the rate of change (the first derivation of the area) when the radius is equal to 5 inches.

Then the first thing we need to do is find the value of t such that the radius is equal to 5 inches.

r(t) = 5 in =  (1/  in/s)*t

       5in*(π s/in) = t

        5*π s = t

So the radius will be equal to 5 inches after 5*π seconds, let's remember that.

Now let's find the first derivate of A(t)

dA(t)/dt = A'(t) = 2*(π*(1/π  in/s)^2*t = (2*π*t)*(1/π  in/s)^2

Now we need to evaluate this in the time such that the radius is equal to 5 inches, we will get:

A'(5*π s) = (2*π*5*π s)*((1/π  in/s)^2

              = (10*π^2  s)*(1/π^2  in^2/s^2) = 10 in^2/s

The rate of change is 10 square inches per second.

4 0
3 years ago
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