Answer: 12-5d
because all you do is flip the expression
the final speed in m/s of the 10.0 kg is 2.53 m/s .
<u>Step-by-step explanation:</u>
Here we have , A 10.0 kg and a 2.0 kg cart approach each other on a horizontal friction less air track. Their total kinetic energy before collision is 96 ). Assume their collision is elastic. We need to find What is the final speed in m/s of the 10.0 kg mass if that of the 2.0 kg mass is 8.0 m/s . Let's find out:
We know that in an elastic collision :
⇒ Total kinetic energy before collision = Total kinetic energy after collision
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , the final speed in m/s of the 10.0 kg is 2.53 m/s .
Answer:
Step-by-step explanation:
y = mx + b
Take any two points and set up 2 equations with 2 unknowns.
I'll start with the first two
y = 4x + b
410 = 4x + b (1)
440 = 6x + b (2)
Subtract (1) from (2)
440 = 6x + b
<u>410 = 4x + b</u> Subtract
30 = 2x Divide by 2
30/2 = 2x/2
x = 15
440 = 6(x) + b
440 = 6*15 + b
440 = 90 + b
b = 350
Now here is what you found.
Her base salary is 350 dollars
Each television she sells brings her an addition 15.
Answer:
$3.49 for the muffin, and $2.96 for the coffee
Step-by-step explanation:
(3.25)(1.075) = 3.49
(2.75)(1.075) = 2.96
How to find the factor to multiply by
1.075 = 1+.075, 7.5% = 7.5/100 = .075