1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
fredd [130]
3 years ago
12

NEED help will give brainliest

Mathematics
2 answers:
Stella [2.4K]3 years ago
6 0

Answer:

B )  -2

Step-by-step explanation:

<u>slope of given points</u>

slope m= \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

The given points are

m = \frac{-4-8}{5-(-1)}

m=\frac{-12}{6}

m=-2

<u>final answer</u> :-

slope of the line is m=-2

harkovskaia [24]3 years ago
3 0
The answer is B -2... you welcome
You might be interested in
NEED HELP WILL MARK BRANLYEST
BlackZzzverrR [31]

Answer:

The first of the rows should go with each other. The 36/125^3 does with the second one. The 6/125^3 goes to the third one. The last row goes with 8/125 cm^3

Step-by-step explanation:

6 0
3 years ago
1.<br> (3x + y = 5<br> (x-4y=32
chubhunter [2.5K]

Answer:

13x=52

x=14

y=-37

plz mark brainliest

8 0
3 years ago
Read 2 more answers
Can someone help me on this
Serggg [28]
I don't know if you still need help. but the answer is the first one.
4 0
3 years ago
Read 2 more answers
Verify that the given point is on the curve and find the lines that are (a) tangent and (b) normal to the curve at the given poi
lara [203]

For each curve, plug in the given point (x,y) and check if the equality holds. For example:

(I) (2, 3) does lie on x^2+xy-y^2=1 since 2^2 + 2*3 - 3^2 = 4 + 6 - 9 = 1.

For part (a), compute the derivative \frac{\mathrm dy}{\mathrm dx}, and evaluate it for the given point (x,y). This is the slope of the tangent line at the point. For example:

(I) The derivative is

x^2+xy-y^2=1\overset{\frac{\mathrm d}{\mathrm dx}}{\implies}2x+x\dfrac{\mathrm dy}{\mathrm dx}+y-2y\dfrac{\mathrm dy}{\mathrm dx}=0\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x+y}{2y-x}

so the slope of the tangent at (2, 3) is

\dfrac{\mathrm dy}{\mathrm dx}(2,3)=\dfrac74

and its equation is then

y-3=\dfrac74(x-2)\implies y=\dfrac74x-\dfrac12

For part (b), recall that normal lines are perpendicular to tangent lines, so their slopes are negative reciprocals of the slopes of the tangents, -\frac1{\frac{\mathrm dy}{\mathrm dx}}. For example:

(I) The tangent has slope 7/4, so the normal has slope -4/7. Then the normal line has equation

y-3=-\dfrac47(x-2)\implies y=-\dfrac47x+\dfrac{29}7

3 0
4 years ago
NCERT SOLUTIONS FOR CLASS 7 <br><br>MATHS <br><br>ALL CHAPTERS<br>​
Galina-37 [17]

Answer:

https://www.learncbse.in/ncert-solutions-for-class-7-maths/

5 0
3 years ago
Other questions:
  • Distance between points (−4, 3) and (−2, −1)?
    15·1 answer
  • Round the following to the nearest hundredth.<br><br> 0.003:<br> 0.057:<br> 0.095:
    6·1 answer
  • If a road has a grade of 30°, this means that it's angle of elevation is 30°. If you travel 1.5 miles on this road, how much ele
    9·1 answer
  • Dical and exponent<br> What is 6<br> in radical form?
    6·1 answer
  • What value of x makes this equation true?
    5·1 answer
  • What is an equation of the line that is parallel to y=5x−7 and passes through (1, 11) ?
    7·2 answers
  • Que número disminuido en 32% es 520
    8·1 answer
  • 342 employees prefer a bonus over extra vacation days from a survey of 450 employees what is the population proportion
    7·1 answer
  • Find the value of x in the equation below. 18 = x - 10
    5·1 answer
  • What is the distance between the points (-5,-4) and (3,-3). ​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!