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3 years ago

10 x 2 tens=_ Tens = ___

Mathematics

2 answers:

motikmotik3 years ago

4 0

10 × 2 tens = 20 tens = 200

laila [671]3 years ago

4 0

Hello there!

Just to get the idea of it, work it out in number form as 10 x 20 = 200.
Then simply place it in.

10 x 2 tens = 20 tens = 200.

Hope This Helps You!
Good Luck :)

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If 36^12-m=6^2m what is the value of m??

skad [1K]

Answer:

$m=6$

Step-by-step explanation:

if 36^12-m=6^2m , find the value of m

$36^{12-m}=6^{2m}$

To make the exponents equal , we need to get the same base.

The base of both sides of equation are not same.

36 can be written as 6^2

$6^{2(12-m)}=6^{2m}$

$6^{24-2m}=6^{2m}$

now base of both sides are same . so we equate the exponents

$24-2m= 2m$

add 2m on both sides

$24=4m$

divide by 4 on both sides

$6=m$

The value of m is 6

5 0

4 years ago

Read 2 more answers

8. Which statement can be represented by the equation shown?<br> 9x-2=8x

Thepotemich [5.8K]

Answer:

A or the 1st one

Step-by-step explanation:

Angelo is making 9 dollars per hour but, loses 2 dollars due to the bus fee. So in math form that would be:

9x - 2

And the second part is Tom makes 8 dollars per hour but doesn't have to pay for bus fee. In math form that would be;

So put that together that would be

9x - 2 = 8x

3 0

3 years ago

When her number is divided by 12, the remainder is 6, what is the remainder when the number is idvided by 9?

pentagon [3]

Remainder: 6 when divided by 12
So 12x6= 72
Original number: 72
72/9= 8
The remainder: 8

3 0

3 years ago

K is the midpoint of JL JK=3x-1 and KL=2x+8 find JL

Masteriza [31]

Answer:

JL = 52

Step-by-step explanation:

It is given in the question that K is the midpoint of JL.

So, JK = KL ......... (1)

Now, given that, JK =3x - 1 and KL = 2x + 8

Therefore, from equation (1), we can write

3x - 1 = 2x + 8

⇒ x = 9

So, JK = 3x - 1 = 3(9) -1 = 26 and KL = 2x + 8 = 2(9) + 8 = 26

Hence, JL = JK + KL = 26 + 26 = 52. (Answer)

3 0

3 years ago

2(a³+b²+11)+1(3+a³+b+11)

Ann [662]

Answer:

$2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36$

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

$2(a^3+b^2+11)+1(3+a^3+b+11)$

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

$2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14$

Therefore, $2(a^3+b^2+11)+1(3+a^3+b+11)$ is equal to:

$2a^3+2b^2+22+a^3+b+14$

Now, combining like terms using the commutative property of addition, we get:

$=(2a^3+a^3)+2b^2+b+(22+14)\\=3a^3+2b^2+b+36$

Therefore, the simplified form is $3a^3+2b^2+b+36$

8 0

4 years ago

10 x 2 tens=_____ Tens = _______

10 x 2 tens=_ Tens = ___