Answer:
6305
StepStep-by-stepStepStep-by-step-by-step-by-step explanation:
multply
Multiply the numerator and denominator by 7×2 = 14 to eliminate the denominators of those fractions:

Rationalize the denominator by multiplying both numerator and denominator by √10:

Lastly, cancel the common factor of 2 in both the numerator and denominator (which comes from 6 = 2×3 and 490 = 2×245):

-5/2 is the slope of thosr points
Photomath is useful for these kinds of problems
Never
they have the same ratio only
congruent triangles have equal sides