Answer:
The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.
Interval Notation:
(
−
∞
,
∞
)
Set-Builder Notation:
{
x
|
x
∈
R
}
Step-by-step explanation:
hope that helps bigger terms
Answer:
here's your answer in the given picture
[ Answer ]
[ Explanation ]
Rewrite 0.12 As A Fraction
-----------------------------
Rewrite Decimal As A Fraction With 1 As A Denominator
0.12 = 
Multiply To Remove Decimal Places
· 
= 
Find GCF, Reduce Fraction
= 
0.12 =
![\boxed{\boxed{[ \ Eclipsed \ ]}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%5B%20%5C%20Eclipsed%20%5C%20%5D%7D%7D)
sqrt (5x - 9) - 1 = x
sqrt(5x - 9) = x + 1
Square both sides:_
5x - 9 = x^2 + 2x + 1
x^2 - 3x + 10 = 0
(x - 5)(x + 2) = 0
x = 5 or -2.
Lets look for for any extraneous solutions:-
x = 5 ; sqrt (5*5-9) - 1 = sqrt16 - 1 = 3 and x = 3 (right hand side of equation)
so x = 5 is a solution
x = -2: sqrt(5*-2 - 9) - 1 = sqrt (-19) - 1 and x = -2 so this is extraneous
Answer:- One solution x = 5
