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Rashid [163]
3 years ago
7

PLEASE HELP!!! WILL GIVE BRANLIEST

Mathematics
1 answer:
Setler79 [48]3 years ago
6 0

Answer:

A

Step-by-step explanation:

becuase you its A

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Find the value of k<br> 4x+y=8<br> y=kx+2<br><br> options<br><br> -4<br> 4<br> -1/4<br> 1/4
nexus9112 [7]

Answer:

4 i think im not sure

Step-by-step explanation:

Subtract yy from both sides of the equation.

4x=8−y4x=8-y

y=kx+2y=kx+2

Divide each term by 44 and simplify.

Tap for more steps...

x=2−y4x=2-y4

y=kx+2

6 0
3 years ago
Find an equation in slope-intercept form for the line with a zero slope and passes through (12, -9). a. x = 12 c. y = 12x - 9 b.
nirvana33 [79]

Answer:

b. y = -9

Step-by-step explanation:

A line with zero slope has no dependence on x. It is simply ...

... y = constant

The constant must be the same as the y-value of the point you want the line to go through. Since the point is (12, -9), the constant is -9 and the equation is ...

... y = -9

3 0
3 years ago
Read 2 more answers
PROPIEDADES DE LA SUMA Y PRUBA DE LA RESTA.
olga2289 [7]
Answer is c la diferencia Ed la Miya’s question el minuendo
3 0
3 years ago
The graphs of the polar curves r = 4 and r = 3 + 2cosθ are shown in the figure above. The curves intersect at θ = π/3 and θ = 5π
Gennadij [26K]
(a)

\displaystyle \frac{1}{2} \cdot \int_{\frac{\pi}{3}}^{\frac{5\pi}{3}} \left(4^2 - (3 + 2\cos\theta)^2 \right) \, d\theta

or, via symmetry

\displaystyle\frac{1}{2} \cdot 2 \int_{\frac{\pi}{3}}^{\pi} \left(4^2 - (3 + 2\cos\theta)^2 \right) \, d\theta

____________

(b)

By the chain rule:

\displaystyle \frac{dy}{dx} = \frac{ dy/ d\theta}{ dx/ d\theta}

For polar coordinates, x = rcosθ and y = rsinθ. Since
<span>r = 3 + 2cosθ, it follows that

x = (3 + 2\cos\theta) \cos \theta \\ &#10;y = (3 + 2\cos\theta) \sin \theta

Differentiating with respect to theta

\begin{aligned}&#10;\displaystyle \frac{dy}{dx} &= \frac{ dy/ d\theta}{ dx/ d\theta} \\&#10;&= \frac{(3 + 2\cos\theta)(\cos\theta) + (-2\sin\theta)(\sin\theta)}{(3 + 2\cos\theta)(-\sin\theta) + (-2\sin\theta)(\cos\theta)} \\ \\&#10;\left.\frac{dy}{dx}\right_{\theta = \frac{\pi}{2}}&#10;&= 2/3&#10;\end{aligned}

2/3 is the slope

____________

(c)

"</span><span>distance between the particle and the origin increases at a constant rate of 3 units per second" implies dr/dt = 3

A</span>ngle θ and r are related via <span>r = 3 + 2cosθ, so implicitly differentiating with respect to time

</span><span />\displaystyle\frac{dr}{dt} = -2\sin\theta \frac{d\theta}{dt} \quad \stackrel{\theta = \pi/3}{\implies} \quad 3 = -2\left( \frac{\sqrt{3}}{2}}\right) \frac{d\theta}{dt} \implies \\ \\ \frac{d\theta}{dt} = -\sqrt{3} \text{ radians per second}
5 0
3 years ago
5 times what equals 0.6
LUCKY_DIMON [66]
.12 Think of it like 5x12=60
3 0
3 years ago
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