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Define x :
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Let the width be x.
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Find Area of the walkway :
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Area = 30x + 30x + 20x + 20x + 4x²
Area = 100x + 4x²
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Find cost of the walkway in term of x:
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1m² = $10
100x + 4x² = 10(4x² + 100x)
(100x + 4x²)m = $(40x² + 1000x)
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Find Width of the walkway :
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The budget is $6000
40x² + 1000x = 6000
40x² + 1000x - 6000 = 0
x² + 25x -150 = 0 //Divide by 40 through
(x - 5)(x + 30) = 0 //Factorise
x = 5 or x = -30 (Rejected, width cannot be negative)
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Answer: The width can be 5m wide.
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Hey there!
We'll be writing them in slope-intercept form. Slope intercept form is defined as:
y = mx + b
With m being the slope and b as the y-intercept. Now, we can just plug them in.
1)
y = -3x - 2
Slope = -3
Y intercept = -2
2) y = 5x + 7
Slope = 5
Y intercept = 7
3) y = -3/4x + 3
Slope = -3/4
Y intercept = 3
4) y = 5/2x - 6
Intercept = -6
Slope = -5/2
Hope this helps!
C. 5/2.
You can get the scale factor by putting the measurements of similar sides on a fraction,
In this case 20/8 =5/2, 10/4 = 5/2
Answer:
-17 = x/-3 for x.
Step-by-step explanation:
Check the picture below.
since chords NQ and MP cross the center of the circle at R, that means that those two chords are diametrical chords and the angles made by both are vertical angles and thus twin angles, namely both are 18° as you see in the picture, so the angle NMP in magenta is really 162° + 18° + 18° = 198°, and we know the radius NR is 8.
![\textit{arc's length}\\\\ s=\cfrac{r\pi \theta }{180}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ r=8\\ \theta =198 \end{cases}\implies s=\cfrac{(8)\pi (198)}{180}\implies s\approx 27.6](https://tex.z-dn.net/?f=%5Ctextit%7Barc%27s%20length%7D%5C%5C%5C%5C%20s%3D%5Ccfrac%7Br%5Cpi%20%5Ctheta%20%7D%7B180%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20%5Ctheta%20%3D%5Cstackrel%7Bdegrees%7D%7Bangle%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D8%5C%5C%20%5Ctheta%20%3D198%20%5Cend%7Bcases%7D%5Cimplies%20s%3D%5Ccfrac%7B%288%29%5Cpi%20%28198%29%7D%7B180%7D%5Cimplies%20s%5Capprox%2027.6)
