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3 years ago

Pls help meeethank you thank you thank you thank you

Mathematics

2 answers:

olga_2 [115]3 years ago

6 0

Answer:

See below

Step-by-step explanation:

11 box 1: 12

11 box 2: 101

12 box 1: 80

12 box 2: 80

12 box 3: 80

13 box 1: 16

13 box 2: 16

13 box 3: 76

20 = y + 12

20 - 12 = y + 12 - 12

8 = y

x + 2 = 19

x + 2 - 2 = 19 - 2

x = 17

z - 313 = 176

z - 313 + 313 = 176 + 313

z = 489

natka813 [3]3 years ago

5 0

Answer:

See below

Step-by-step explanation:

11 box 1: 12

11 box 2: 101

12 box 1: 80

12 box 2: 80

12 box 3: 80

13 box 1: 16

13 box 2: 16

13 box 3: 76

20 = y + 12

20 - 12 = y + 12 - 12

8 = y

x + 2 = 19

x + 2 - 2 = 19 - 2

x = 17

z - 313 = 176

z - 313 + 313 = 176 + 313

z = 489

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Answer:

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3 years ago

Simplify the polynomial by combining like terms. 3.63x2 - 4.54x + 7.96x2 +9.85 -3.12x

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Answer:

11.59x² -7.66x + 9.85

Step-by-step explanation:

3.63x² - 4.54x + 7.96x² +9.85 -3.12x

11.59x² -7.66x + 9.85

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3 years ago

Read 2 more answers

Point A is located at (-2, 2), and point M is located at (1,0). If point M is the midpoint of AB, find the location of point B.

bezimeni [28]

Answer:

B. $B = (4,-2)$

Step-by-step explanation:

GIven that $A = (-2, 2)$ and $M = (1, 0)$ , and that point M is the midpoint of AB, the midpoint can be determined as a vectorial sum of A and B. That is:

$M = \frac{1}{2}\cdot A + \frac{1}{2}\cdot B$

The location of B is now determined after algebraic handling:

$\frac{1}{2}\cdot B = M - \frac{1}{2}\cdot A$

$B = 2\cdot M -A$

Then:

$B = 2\cdot (1,0)-(-2,2)$

$B = (2\cdot 1, 2\cdot 0)-(-2,2)$

$B = (2,0) -(-2,2)$

$B = (4,-2)$

Which corresponds to option B.

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2 years ago

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Step-by-step explanation:

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3 years ago

Select the equivalent expression . ( 8^ -5 2^ -2 )^ -4 =?

Vikki [24]

Answer: C

Step-by-step explanation:

When there is division inside a set of parentheses, you can distribute the power to each term. When you take a power to another power, you multiply the powers.

-5 x -4 = 20

-2 x -4 = 8

So your answer is:

$\frac{8^2^0}{2^8}$

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3 years ago