There is no restriction on the domain because there is a cube root for all real values positive or negative. So you can solve this as there are no extraneous solutions...
Cube both sides...
2x-4=-8
2x=-4
x=-2
The sum of any geometric sequence, (technically any finite set is a sequence, series are infinite) can be expressed as:
s(n)=a(1-r^n)/(1-r), a=initial term, r=common ratio, n=term number
Here you are given a=10 and r=1/5 so your equation is:
s(n)=10(1-(1/5)^n)/(1-1/5) let's simplify this a bit:
s(n)=10(1-(1/5)^n)/(4/5)
s(n)=12.5(1-(1/5)^n) so the sum of the first 5 terms is:
s(5)=12.5(1-(1/5)^5)
s(5)=12.496
as an improper fraction:
(125/10)(3124/3125)
390500/31240
1775/142
Answer:
Which of the following are possible rational roots of the polynomial function? Check all that apply. F(x) = 5 x2-3x+3
A. ±3
B. ±1
<em><u>C. ±1/3</u></em>
D. ±5
E. ±1/5
Answer:
511054077591
Step-by-step explanation:
Answer: 75+20=75 and 20+75=20
Step-by-step explanation:
