Answer:
In a neutral molecule, the sum of the bonding valance electrons must be equal. So the products of the negative element and its charges and the positive element and its charge must be equal.
Explanation:
C1×N1 = C2×N2
If we have a 3 valance electrons , the 'A' charge will be either +3 or -5 for a full octet and valance electron in 'B' atoms will mostly result in acquisition of additional electrons (2) for an octet and relative charge of -2.
Balancing the two,
3 × A = -2 × B
To be equal, A = 2 and B = 3
Therefore, A²B³
I think the answer is 4 carbon dioxide
Wavelength and Frequency are inversely related to each other as,
υ = c / λ ----- (1)
Where;
υ = Frequency = 2.40 × 10¹³ s⁻¹
c = 2.99 × 10⁸ ms⁻¹
λ = ?
Solving equation 1 for λ,
λ = c / υ
Putting Values,
λ = 2.99 × 10⁸ ms⁻¹ ÷ 2.40 × 10¹³ s⁻¹
λ = 0.00001245833 m
Or,
λ = 1.24 × 10⁻⁵ m
Use the Keq equation.. concentraion of products divided by concentration of reactants at equilibrium. (with coefficients as exponents, none in this case reaction is balanced)
Keq = [PCl5] / ([PCl3] [Cl2])
fill in given values and solve for [Cl2] using algebra. Im just going to sub in "c" for the unknown.
0.00094 = 0.44 / 0.33c
0.0003102c = 0.44
c = 1418.44 mol/L
When the compound PbI₂ dissolves, it dissociates as follows;
PbI₂ --> Pb²⁺ + 2I⁻
Molar solubility is the number of moles dissolved in 1 L of solution
A saturated solution is when the maximum amount of solute is dissolved in the solution.
Molar solubility of Iodide when solution is saturated is 2.7 x 10⁻³ mol/L, then solubility of Pb²⁺ is (2.7 x 10⁻³ mol/L) / 2 = 1.35 x 10⁻³ mol/L
ksp is the solubility product constant that can be calculated as follows;
ksp = [Pb²⁺][I⁻]
ksp = (1.35 x 10⁻³ mol/L) x (2.7 x 10⁻³ mol/L)²
= 1.35 x 10⁻³ x 7.29 x 10⁻⁶
= 9.8 x 10⁻⁹