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labwork [276]
2 years ago
8

S]

Chemistry
1 answer:
Karolina [17]2 years ago
6 0
Can you reword it im confused
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Which atmospheric gas has the greatest effect on the weather conditions associated with an air mass? 1. Oxygen 2. Nitrogen 3. Me
Ratling [72]
Methane might be the answer
i hope this helps
5 0
3 years ago
N₂ + 3H2 → 2NH3
Rainbow [258]

Answer:

187 moles NH₃

Explanation:

To find the amount of ammonia formed, you need to multiply the given value by the mole-to-mole ratio consisting of both relevant molecules. The mole-to-mole ratio is made up of the molecules' coefficients in the balanced equation. The desired unit should be placed in the numerator of the ratio. The final answer should have 3 sig figs to reflect the lowest amount of sig figs among the given values.

1 N₂ + 3 H₂ ----> 2 NH₃
^                         ^

93.5 moles N₂          2 moles NH₃
----------------------  x  -------------------------  =  187 moles NH₃
                                    1 mole N₂

3 0
1 year ago
Read 2 more answers
A chemist must prepare of hydrochloric acid solution with a pH of at . He will do this in three steps: Fill a volumetric flask a
Eva8 [605]

Answer:

1.7 mL

Explanation:

<em>A chemist must prepare 550.0 mL of hydrochloric acid solution with a pH of 1.60 at 25 °C. He will do this in three steps: Fill a 550.0 mL volumetric flask about halfway with distilled water. Measure out a small volume of concentrated (8.0 M) stock hydrochloric acid solution and add it to the flask. Fill the flask to the mark with distilled water. Calculate the volume of concentrated hydrochloric acid that the chemist must measure out in the second step. Round your answer to 2 significant digits.</em>

Step 1: Calculate [H⁺] in the dilute solution

We will use the following expresion.

pH = -log [H⁺]

[H⁺] = antilog - pH = antilog -1.60 = 0.0251 M

Since HCl is a strong monoprotic acid, the concentration of HCl in the dilute solution is 0.0251 M.

Step 2: Calculate the volume of the concentrated HCl solution

We want to prepare 550.0 mL of a 0.0251 M HCl solution. We can calculate the volume of the 8.0 M solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂/C₁

V₁ = 0.0251 M × 550.0 mL/8.0 M = 1.7 mL

3 0
3 years ago
Nitrogen dioxide reacts with water to form nitric acid and nitrogen monoxide according to the equation: 3NO2(g)+H2O(l)→2HNO3(l)+
Vera_Pavlovna [14]

Answer:

5 moles of NO₂ will remain after the reaction is complete

Explanation:

We state the reaction:

3NO₂(g) + H₂O(l) → 2HNO₃(l) + NO(g)

3 moles of nitric oxide can react with 1 mol of water. Ratio is 3:1, so we make this rule of three:

If 3 moles of nitric oxide need 1 mol of water to react

Then, 26 moles of NO₂ may need (26 .1) / 3 = 8.67 moles of H₂O

We have 7 moles of water but we need 8.67 moles, so water is the limiting reactant because we do not have enough. In conclusion, the oxide is the reagent in excess. We can verify:

1 mol of water needs 3 moles of oxide to react

Therefore, 7 moles of water  will need (7 .3)/1 = 21 moles of oxide

We have 26 moles of NO₂ and we need 21, so we still have oxide after the reaction is complete. We will have (26-21) = 5 moles of oxide that remains

5 0
2 years ago
You are examining the DNA sequences that code for the enzyme phosphofructokinase in skinks and Komodo dragons. You notice that t
jek_recluse [69]

Answer: D. Mutation in coding sequences are more likely to be deleterious to the organism than mutations in noncoding sequences.

Explanation: It was not likely to be that the coding sequences are replicated more often. The only possible explanation is that the mutations in coding is more likely to be deleterious to the organism than mutations because it is in a non coding sequence.

8 0
2 years ago
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