<span>Let A be the center of a circle and two angles at the adjacent center AOB and BOC. Knowing the measure of the angle AOB = 120 and the measure BOC = 150, find the measures of the angles of the ABC triangle.
</span>solution
Given the above information;
AC=AB, therefore ABC is an isosceles triangle.
therefore, BAO=ABO=(180-120)/2=30
OAC=OCA=(180-90)/2=45
OBC=BCO=(180-150)/2=15
THUS;
BAC=BAO+OAC=45+30=75
ABC=OBA+CBO=15+30=45
ACB=ACO+BCO=15+45=60
Answer
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Step-by-step explanation:
The area of the triangle is 4 units²
<h3>What is the area of a triangle?</h3>
The area of a triangle is the half the base multiplied with the height of that triangle
Area = 1/ 2 × b × h
From the figure given,
base = 7 - 3 = 4 units
height = 4 - 2 = 2 units
Area = 1/ 2 × 4 × 2
Area = 1/ 2 × 8
Area = 4 units²
Thus, the area of the triangle is 4 units²
Learn more about a triangle here:
brainly.com/question/1475130
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linear function; growth factor of 4
