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Wittaler [7]
3 years ago
6

#You may modify the lines of code above, but don't move them! #When you Submit your code, we'll change these lines to #assign di

fferent values to the variables. #There's an easy way to do this exercise, and a hard way. For #a hint on the easier way, revisit the sample answers for the #previous coding exercise. # #Above we've created a variable called mystery_string. Write #some code that will print the first letter of the string on #the first line, the first two letters on the second line, #the first three letters on the third line, etc., until it #prints the entire string on the last line. #
Computers and Technology
1 answer:
Musya8 [376]3 years ago
8 0

Answer:

The solution code is written in Python:

  1. mystery_string = "Programming"
  2. output = ""
  3. for x in mystery_string:
  4.    output += x  
  5.    print(output)

Explanation:

Firstly, create a variable mystery_string to hold a random string (Line 1).

Create an output variable to hold an output string (Line 2).

Create a for-loop to traverse the mystery_string character by character (Line 4). In the iteration, get a character from the mystery_string, and concatenate it with output string (Line 5). Print the output string (Line 6) before proceed to the next iteration.

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Lilit [14]
On A Windows machine, you can use the netsh command.
<span>netsh interface ip set dns name="Local Area Connection" static 208.67.222.222

All the steps below means you have access to the router via Telnet or physical access  and it already has a valid configuration (except the DNS)
On a Cisco Router is:
</span><span>Step 1:  <span>enable 
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5 0
3 years ago
Which microsoft operating system started the process of authenticating users with a user name and password?
11111nata11111 [884]
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5 0
3 years ago
What is the khan academy game where it is a block having to jump over lava and is an endless runner
saw5 [17]

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Explanation:

5 0
3 years ago
QUESTION 6 Which of the following is a class A IPv4 address? a. 118.20.210.254 b. 183.16.17.30 c. 215.16.17.30 d. 255.255.0.0
shepuryov [24]

Answer:

a. 118.20.210.254

Explanation:

Here are the few characteristics of Class A:

First bit of the first octet of class A is 0.

This class has 8 bits for network and 24 bits for hosts.

The default sub-net mask for class A IP address is 255.0.0.0

Lets see if the first bit of first octet of 118.20.210.254 address is 0.

118 in binary (8 bits) can be represented as : 1110110

To complete 8 bits add a 0 to the left.

01110110

First bit of the first octet of class A is 0 So this is class A address.

For option b the first octet is : 183 in the form of bits = 10110111 So it is not class A address

For option c the first octet is 215 in the form of bits = 11010111 So it is not class A address

For option d the first octet is 255 in the form of bits = 11111111. The first bit of first octet is not 0 so it is also not class A address.

3 0
3 years ago
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7 0
3 years ago
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