Can anybody please help me out with this question please I would really appreciate it so much. please and thank you .
1 answer:
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Answer:
a)How many different ways can you allocate the 22 students to the projects? =2300
b) how many different ways can you allocate the 22 students to the projects= 286
Step-by-step explanation:
check attachment for detail explanations
Answer:
VW = √2
Step-by-step explanation:
y = x+1
x²+y²+2x+2y+1=0 (x²+2x+1) + (y²+2y+1) = 1
(x+1)² + (y+1)² = 1 : Circle: (x-h)² + (y-k)² = r² Center (O): (h , k) = (-1 , -1) r = 1
solve for roots: x²+(x+1)²+2x+2(x+1)+1=0
2x² + 6x + 4 = 0 x²+3x+2=0
(x+1)(x+2)=0
x = -1 or x = -2
y = 0 or y = -1
V and W: (-1 , 0) and (-2 , -1) forms a 90° center angle
√vw = √1²+1² = √2
