Answer:
Step-by-step explanation:
<u>Using Pythagorean Theorem first to find EC</u>
<u>Given that:</u>
AE = EC
AE = 12 cm
Now,
AB = AE + EB
AB = 12 + 5
AB = 17 cm
<u>ABCD is a trapezoid / trapezium</u>
So,
Area of Trapezium = 
Where AB = 17 , DC = 8 and EC = 12
Area of Trapezium = 
Area of Trapezium = (25)(6)
Area of Trapezium = 150 cm²
(b/2)^2=(−5)^2
x^2−10x+(−5)^2=<span>24+<span>(−5)^<span>2
</span></span></span><span><span>x^2−10x+25</span>=49
</span><span><span>(x−5)^</span>2</span>=<span>49 (square root)
</span><span>(<span>x<span>−5</span></span>)</span>=<span>±<span>7
x-5=7 => x=12
x-5=-7 => x=-2</span></span>
Answer:
I hope this help
Step-by-step explanation:
x + y - 5
subtract 0 from the equation above
We first of all calculate our sample size. The number of ways of generating two letter and four digits in a way that repeatition is allowed is:
26^2 x 10^4 = 676 x 10000 = 6,760,000.
Therefore, there are 6,760,000 possible number combinations for the lottery.
Probability of winning the first prize = 1/6,760,000
Probability of winning the second prize is 2/6,760,000 = 1/3,380,000
Probability of winning the third prize is 10/6,760,000 = 1/676,000
Probability of winning nothing is (6,760,000 - 13)/6,760,000 = 6,759,987/6,760,000 *[there are 13 winnings in all]
Expected winning from the lottery = (1/6,760,000) x (100,000 - 0.33) + (1/3,380,000) x (50,000 - 0.33) + (1/676,000) x (1,000 - 0.33) + (6,759,987/6,760,000) x (-0.33) = 0.0148 + 0.0148 + 0.0015 - 0.3300 = -0.30
Therefore, the expected winning is a loss of 30 cents.
This means that it is not worth 33 cents to enter this lottery.
You’ll have to get rid of the ones around it by doing the opposites (+ goes to - and divine going to multiply)
