Question

Solve the following equation algebraically: 3x^2=48

Answer 1

3x^2 = 48; Divide both sides by 3 to isolate the variable.

3x^2 / 3 = x^2; 48 / 3 = 16

x^2 = 16; Square root both sides to determine the value for x.

x^2 / x = x; sq rt of 16 = 4.

Your ending equation is x = 4.

I hope this helps!