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Zanzabum
3 years ago
10

Robert's family brings six gallons of water for the players on the football team. If one gallon of water contains 128 fluid ounc

es, how many fluid ounces are in six gallons.
Mathematics
2 answers:
Pachacha [2.7K]3 years ago
7 0
The answer is 768. 128x6=768
levacccp [35]3 years ago
6 0

Answer:

768

Step-by-step explanation:

128*6=768

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This is correct? I need help please :(
Leto [7]

Answer:

well, we only no that

2l + 2w is 80

(lengths and widths on all 4 sides

and that w * l is A

so the function should be w times what's left for l, but also expressed by something with w

2l + 2w = 80 | -2w

2l = 80 -2w | devide by 2

l = 80 - w

now we can substitute l in

A = w * l

so that we only need w's

A(w) = w * (80-w)

for any w it will give us the area, makes only sense for 0<w<80

8 0
3 years ago
Read 2 more answers
I am trying to understand how to solve for X, then solve the equation
Alina [70]

Answer:

x = 16

m<Y = 34°

Step-by-step explanation:

∆XYZ is an isosceles ∆. An isosceles ∆ has two equal sides, as well as the bases of the isosceles triangle are congruent. In this case, therefore:

<X = <Z

(6x - 23)° = (4x + 9)

Solve for x

6x - 23 = 4x + 9

Collect like terms

6x - 4x = 23 + 9

2x = 32

Divide both sides by 2

x = 16

m<Y = 180° - (m<X + m<Z) (sum of ∆)

m<Y = 180 - ((6x - 23) + (4x + 9))

Plug in the value of x

m<Y = 180 - ((6(16) - 23) + (4(16) + 9))

m<Y = 180 - (73 + 73)

m<Y = 34°

5 0
3 years ago
What is the product of -2 1/4 and 4 1/2
solmaris [256]
The answer would be <span>-10.125</span>
5 0
3 years ago
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U-3/4=4 please help me ty
Ne4ueva [31]
To solve the equation:

\frac{u - 3}{4}  = 4 \\ \frac{u - 3}{4}  \times 4 = 4  \times 4\\ u - 3 = 4 \times 4 \\ u - 3 + 3 = 16 + 3 \\ u = 16 + 3 \\ u = 19

Therefore, the answer is u=19.

Hope it helps!
8 0
4 years ago
Read 2 more answers
If the base is 8 in. and the height is 7 in. What is the area?
kap26 [50]

Answer:

The formula of area is Pi×R×R

and then you add all sides and answer of your question is 30cm

8 0
3 years ago
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