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____ [38]
3 years ago
10

a student received a coupon for 17% off the total purchase price at a clothing store. let b be the original price of the purchas

e. use the expression b - 0.17b for the new price of the purchase. write an equivalent expression by combining like terms.
Mathematics
1 answer:
goldenfox [79]3 years ago
4 0
The expression could be 0.83(x).
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Gale wants to compare the cost of the events.
Lera25 [3.4K]

#a

The table represents all possibilities.

  • Yes its possible .
  • The table may represent Aquarium fee more or least etc.

#b

The carnival always costs the least.

  • No its possible but not always .
  • Aquarium fee is 14.50 on the other hand carnival fee starts at 15.55.

#c

The aquarium always costs the move.

  • Impossiible

8 0
2 years ago
Please help quickly !!
Alisiya [41]

Answer:

answer is 26000000

Step-by-step explanation:

10+14/7×-8=26

26 × 1000000=26000000

plz follow and like and make brainliest answer

4 0
3 years ago
If (x+5) and (x+2) are the factors, then the solutions are______ and ______. *
tangare [24]
X = -2 and -5
You can set both equal to 0 to find the answers.
5 0
3 years ago
8. 37.5 ÷2.5 , can y'all please help me with this one and I'm Soo close to getting an 100​
kari74 [83]

Answer:

15

Step-by-step explanation:

37.5÷2.5 goes in 15 times

3 0
3 years ago
Read 2 more answers
The area of a right triangle is sixty square centimetres. Its base is one centimetre less than twice its height. If the base and
NemiM [27]

Answer:

5. None of the above

Step-by-step explanation:

We have this information:

A = 60 cm2

b = 2*h - 1

Let's find out b and h:

The equation of the are of a triangle is A = (b*h)/2, if we replace it with our information, we have

60 = ((2*h - 1) * h)/2\\ 120 = 2*h^2 - h\\ 0 = 2*h^2 - h - 120

Let's find h with the quadratic formula:

\fbox {Quadratic formula:}  \frac{-b\pm\sqrt{b^2-4ac}}{2a}

h = \frac{-(-1)\pm\sqrt{(-1)^2-4*2*(-120)}}{2*2} = \frac{1\pm\sqrt{961}}{4} = \frac{1\pm\ 31}{4}

h = 8 or h = -7.5

But h represents the height of the triangle, so it has to be a positive number, that's h = 8.

If we replace this in the equation we had for b, we have that b = 2*8 - 1 = 15.

Now we can calculate the hypotenuse with the Pythagorean equation  

\fbox {Pythagorean equation:} <em>The square of the length of the hypotenuse (the side opposite the right angle) of a right triangle is equal to the sum of the squares of the two legs (the two sides that meet at a right angle). </em>

The base and the height are our legs. We will use "H" for the hypotenuse

H^2 = b^2 + h^2 = 15^2 + 8^2 = 289\\ H = \sqrt {289} = 17

H = 17

If we decrease the base and the height by 2 centimeters, we have  

b' = 15 - 2 = 13 and h' = 8 - 2 = 6

With this, let's calculate the new hypotenuse:

H'^2 = b'^2 + h'^2 = 13^2 + 6^2 = 205\\ H' = \sqrt {205} \approx 14.3

H' \approx 14.3

So, the hypotenuse decreases H - H' \approx 17 - 14.3 = 2.7

3 0
3 years ago
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