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If 30% of his collection is 12 cars, then we can use the fraction
30/12=100/x
x=40
1: 8 faces and 9 with the base 9 vertices and 16 edges
2: 3 faces and 5 with the bases 6 vertices and 9 edges
3: 3 faces and 4 with the base 4 vertices and 6 edges
Hope this can help you.
1st it: g(2)=3(2)=6 || 2nd it: g^2(2)=3(6)=18 || 3rd it: g^3(2)=3(18)=54
