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Helga [31]
3 years ago
11

Simplify tan 9x - tan 5x / 1 + tan 9x tan 5x.

Mathematics
1 answer:
ANTONII [103]3 years ago
6 0

Simplification of \frac{\tan 9 x-\tan 5 x}{1+\tan 9 x \tan 5 x}  is tan⁡ 4x

<u>Solution: </u>

By using sum-difference formula for tangent,  

Tangent of difference between two angles is written as,

\tan (x-y)=\frac{\tan x-\tan y}{1+\tan x \tan y}(\text { Equation } 1)

By comparing the above equation 1 with \frac{\tan 9 x-\tan 5 x}{1+\tan 9 x \tan 5 x}   ,  

we get x = 9x and y = 5x

By substituting  x =  9x and y = 5x in equation 1,

\begin{array}{l}{\tan (9 x-5 x)=\frac{\tan 9 x-\tan 5 x}{1+\tan 9 x \tan 5 x}} \\\\ {\tan (4 x)=\frac{\tan 9 x-\tan 5 x}{1+\tan 9 x \tan 5 x}} \\\\ {\text { Therefore, } \frac{\tan 9 x-\tan 5 x}{1+\tan 9 x \tan 5 x}=\tan 4 x}\end{array}

Hence by using difference formula for tangent,  \frac{\tan 9 x-\tan 5 x}{1+\tan 9 x \tan 5 x}  is simplified as tan⁡4x

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Step-by-step explanation:

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solve for "w", to see what critical points you get, and then run a first-derivative test on them, for the minimum

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8 0
3 years ago
Prove identity tan 3x−tan 2x−tanx = tan 3xtan 2xtanx
NeX [460]
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7 0
3 years ago
Help please!
larisa86 [58]

Answer:

The point at (-7, -5) = a

The point at (9, 3) = b

The point at (-3, 7) = c

The "a" point of the triangle is 12 units away from the center point.

So, 12 x 1/4

=> 12/4

=> 3

So, the "a" point of the dilated figure is  3 units left from the center.

=> So, the dilated "a" point is at (2, -5)

The "b" point is 8/4 (= rise/run = y-axis / x-axis) from the center point.

=> 8/4 = 2

So, the "b" point of the dilated figure is 1 unit right and 2 units up from the center point.

=> So, the dilated "b" point is at (6, -3)

The "c" point is 12/8 units away from the center point.

=> 12/8 x 1/4

=> 3/2

So, the "c" point of the dilated figure is 3 units up and 2 units left from the center point.

=> So, the dilated "c" point is at (3, -2)

7 0
3 years ago
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